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Anna71 [15]
3 years ago
9

1. Using the formula above, complete this task.

Engineering
1 answer:
Pachacha [2.7K]3 years ago
8 0

Answer:

gfbhjdskmlgtg

Explanation:

grtwhjyeywhtagsfdd

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John, a team member, has completed e0 - agile for beginners he wants to contribute to tcs agile vision. he wants to find out wha
Jet001 [13]

Answer:

John should detail his Scrum Master.

Explanation:

The Team Lead or Scrum Master coordinates the tasks of individual team members and supports the progress of the team. The Scrum Master usually receives instructions from the Product Owner and then ensures that the tasks are performed accordingly.  She also coaches the Development Team and works with the Product Owner to carry out daily development activities.  She also drives the Scrum Values and Principles, ensuring that the team members understand and practice them.

7 0
3 years ago
The best saw for cutting miter joints is the
ZanzabumX [31]

Answer:

The best saw for cutting miter joints is the backsaw.

Add-on:

i hope this helped at all.

6 0
3 years ago
What is the metal removal rate when a 2 in-diameter hole 3.5 in deep is drilled in 1020 steel at cutting speed of 120 fpm with a
Studentka2010 [4]

Answer:

a) the metal removal rate is 14.4 in³/min

b) the cutting time is 0.98 min

Explanation:

Given the data from the question

first we find the rpm for the spindle of the drilling tool, using the equation

Ns = 12V/πD

V is the cutting speed(120 fpm) and D is the diameter of the hole( 2 in)

so we substitute

Ns = 12 × 120 / π2

Ns = 1440 / 6.2831

Ns = 229.18 rmp

Now we find the metal removal rate using the equation

MRR = (πD²/4) Fr × Ns

Fr is the feed rate( 0.02 ipr ),

so we substitute

MRR = ((π × 2²)/4) × 0.02 × 229.18

MRR = 14.3998 ≈ 14.4 in³/min

Therefore the metal removal rate is 14.4 in³/min

Next we find the allowance for approach of the tip of the drill

A = D/2

A = 2/2

= 1 in

now find the time required to drill the hole

Tm = (L + A) / (Fr × Ns)

Lis the the depth of the hole( 3.5 in)

so we substitute our values

Tm = (3.5 + 1) / (0.02 × 229.18  )

Tm = 4.5 / 4.5836

Tm = 0.98 min

Therefore the cutting time is 0.98 min

8 0
3 years ago
tech A says that a Hall-effect sensor can be used in an electronic ignition system. Tech B says that an optical-type sensor can
Alex

Answer:

<em>Both Tech A and Tech B are correct.</em>

<em>Explanation:</em>

<em>The Hall effect sen sensor are used to control displacements and rotations of various body components  of the vehicles, engine vibrations , and the ignition   system</em>

<em>The  optical-type sensor converts rays of light  into electronic signals. It measures the quantity physically of which the translates to a form that is understandable or readable  by an instrument. An optical sensor is larger part of a  system that integrates light sources, a device for measuring  and the optical sensor, which therefore is usually  connected to an electrical trigger.</em>

6 0
3 years ago
2.1 What is the minimum number of pins required for a so-called dual-op-amp IC package, one containing two op amps? What is the
cupoosta [38]

Answer:

8 for dual-op-amp package, and 14 for quad-op-amp

Explanation;

This is because every op-amp has 2 input terminal 4 pns

So one output terminal that is 2 pins which are required for power

and the same for a minumum number of pins required by quad op amp which is 14

5 0
3 years ago
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