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Answer:
The ratio of the mass of oxygen inhaled for each breath at this high altitude compared to that at sea level is 64.7 %
Explanation:
Mass of air at sea level is given by;
Mass of air at 14,200 ft altitude is given by;
The ratio of the mass of oxygen at high altitude to that at sea level is given by;
density of air at sea level,
density of air at 10,000 ft = 0.001756 slug/ft³
density of air at 14,200 ft = x
density of air at 15,000 ft, = 0.001496 slug/ft³
Interpolate between 10,000 ft and 15,000 ft
The ratio of the mass of oxygen at 14,200 ft to that at sea level is given by;
Therefore, the ratio of the mass of oxygen inhaled for each breath at this high altitude compared to that at sea level is 64.7 %