Answer:
CaCl
2
Explanation:
As with all these problems, we assume a
100
⋅
g
of compound, and divide through by the ATOMIC masses of each component element:
Moles of calcium
=
36.1
⋅
g
40.08
⋅
g
⋅
mol
−
1
=
0.901
⋅
mol
.
Moles of chlorine
=
63.9
⋅
g
35.45
⋅
g
⋅
mol
−
1
=
1.802
mol
.
We divide each molar quantity through by the smallest molar quantity (that of calcium) to give an empirical formula of
CaCl
2
.
For ionic materials, we do not speak of the molecular formula, and the empirical formula is the formula we quote for reference.
Answer:
H must pair with Fluorine, Oxygen, or Nitrogen
Explanation:
water has polar covalent bonds, the intermolecular forces are hydrogen bonds, London and Dipole forces
We are using the General gas equation P x V/K = P x V/K
1. P = 1atm V=500ml so PxV= 500 at 6.5km P = 0.5atm V = ? so P xV = 0.5 x V
(We don't have to worry about temperature!) 500 = 0.5 x V so V = 1000ml
2. NO CHANGE in pressure here so we have V/K V=2.75 K = 20 + 273=293 so V/K= 2.75/293
Next set V = 2.46 K = ? so V/K = 2.46/K then 2.75/293= 2.46/K so K=(293/2.75)x2.46
=262 K
Convert back to Celsius 262 - 273 = -11 C
It's raining so I have to rescue the laundry!
Laundry rescued!
3.Now we have to use all three variables. I am using 273K and 100kPa for STP.
P = 100 V = 700 K = 273 These are altered P - unknown, V = 200 K = 273+30=303
!00 x 700/273 = 256.4 this is equal to P x 200/303 = P x 0.66
so P = 256.4/0.66 = 388.48kPa
Answer:
D) speed
Explanation:
Reaction rates can be affected by several factors, including concentration, temperature, surface area and presence of a catalyst. Increasing concentration increases the number of effective collisions. Increasing temperature increases the kinetic energy of the particles, leading to more effective collisions
Answer:
its not c or d because we know nothing will happen to the bow- so its up to a and b- making the answer b :V
Explanation: