The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Probability that one is hired ans one not:
P ( A ) = (2 C 1 * 4 C 4) / 6 C 5 =
= ( 2 * 1 ) / 6 = 2/9 = 1 / 3
Answer: 1/3 or 33.33%
It is different because you are doing a different method to complete the problem. It is the same because it ends up with the same answer, provided you complete the process correctly.
Answer:
2
Step-by-step explanation:
Answer:
A. 2
Step-by-step explanation:
Part 2 of the graph is the only part where the line is decreasing. The rest of the parts are either horizontal or increasing
