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julia-pushkina [17]
2 years ago
9

Describe the main energy transformations that occur when an apple falls from a tree? ​

Physics
1 answer:
blondinia [14]2 years ago
7 0

Answer:

Kinetic energy

Explanation:

When an apple falls from a tree it has to do with the energy from gravity. Gravity energy turns into kinetic energy once its in motion.

Sorry if im wrong

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Please select the word from the list that best fits the definition
lina2011 [118]

Answer:

A subculture.

Explanation:

  • Aspects of a group that is based on the shared values and belief systems and the norms and behaviors aspects that are only a part of the subsection of society are called as subcultures. Like the goths, hippies, etc as its nor accepted by the entire population.
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3 years ago
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Which describes the formation of Horizon B?
Finger [1]

c-undergoes the most change

Explanation:

Horizon B is the layer in a soil profile that has undergone the most change.

A section through a typical soil reveals many of the different layers.

The rock layers are divided into sections which are called horizons.

 Horizon O is the organic matter

  Horizon A is the top soil

  Horizon B is the subsoil.

The subsoil of horizon B is the layer that undergoes the most change. It materials are constantly being leached away from this layer by chemical weathering. Some of the processes here accounts for it typical reddish brown color.

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3 years ago
Which statement is true about the relationship between carrying capacity and population size?
TiliK225 [7]
Carry capacity determines maximum population size
8 0
3 years ago
The 49-g arrow is launched so that it hits and embeds in a 1.45 kg block. The block hangs from strings. After the arrow joins th
Dimas [21]

Answer:

the initial speed of the arrow before joining the block is 89.85 m/s

Explanation:

Given;

mass of the arrow, m₁ = 49 g = 0.049 kg

mass of block, m₂ = 1.45 kg

height reached by the arrow and the block, h = 0.44 m

The gravitational potential energy of the block and arrow system;

P.E = mgh

P.E = (1.45 + 0.049) x 9.8 x 0.44

P.E = 6.464 J

The final velocity of the system after collision is calculated as;

K.E = ¹/₂mv²

6.464 = ¹/₂(1.45 + 0.049)v²

6.464 = 0.7495v²

v² = 6.464 / 0.7495

v² = 8.6244

v = √8.6244

v = 2.937 m/s

Apply principle of conservation of linear momentum to determine the initial speed of the arrow;

P_{initial} = P_{final}\\\\mv_{arrow} + mv_{block} = (m_1 + m_2)V\\\\0.049(v) + 1.45(0) = (0.049 + 1.45)2.937\\\\0.049v = 4.4026\\\\v = \frac{4.4026}{0.049} \\\\v = 89.85 \ m/s

Therefore, the initial speed of the arrow before joining the block is 89.85 m/s

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2 years ago
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