Answer:
1. q.
2. 2q.
3. 3q.
4. 6q.
Explanation:
We'll begin by calculating the specific heat capacity of the liquid. This can be obtained as follow:
Mass (m) = 25 g
Change in temperature (ΔT) = 20 °C
Heat (Q) = q
Specific heat capacity (C) =?
Q = MCΔT
q = 25 × C × 20
q = 500C
Divide both side by 500
C = q/500
C = 2×10¯³ qg°C
Therefore, the specific heat capacity of liquid is 2×10¯³ qg°C
Now, we shall determine the heat required to produce the various change in temperature as follow:
2. Mass (m) = 50 g
Change in temperature (ΔT) = 20 °C
Specific heat capacity (C) = 2×10¯³ qg°C
Heat (Q) =?
Q = MCΔT
Q = 50 × 2×10¯³ × 20
Q = 2q.
Therefore, the heat required is 2q.
3. Mass (m) = 25 g
Change in temperature (ΔT) = 60 °C
Specific heat capacity (C) = 2×10¯³ qg°C
Heat (Q) =?
Q = MCΔT
Q = 25 × 2×10¯³ × 60
Q = 3q.
Therefore, the heat required is 3q.
4. Mass (m) = 50 g
Change in temperature (ΔT) = 60 °C
Specific heat capacity (C) = 2×10¯³ qg°C
Heat (Q) =?
Q = MCΔT
Q = 50 × 2×10¯³ × 60
Q = 6q.
Therefore, the heat required is 6q.
