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2 years ago

How far does an object travel if it is moving at a speed of 4 m/s for 3.2 seconds?

Physics

1 answer:

WINSTONCH [101]2 years ago

5 0

Answer:

12.8 meters

Explanation:

m/s means meters per second. So, to find how far it would travel in 3.2 seconds, you would multiply 4 meters every second by 3.2 seconds.

4×3.2=12.8 meters

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Why do planetary scientists hypothesize that the moon formed with a molten surface

Verdich [7]

The oldest lunar rock samples are approximately 4.4 billion years old and composed of anorthosite, a mineral that crystallizes and rises to the top of a lava ocean.

5 0

3 years ago

Density of water 1000kgper m^3 What will be the volume of 3500 kg water

skad [1K]

Answer:

The volume of water is 3.5 cubic meter

Explanation:

Density

The density of a substance or material is the mass per unit volume. The density varies with temperature and pressure.

The formula to calculate the density of a substance of mass (m) and volume (V) is:

$\displaystyle \rho=\frac{m}{V}$

We are given the density of water as $\rho=1,000\ kg/m^3$ .It's required to find the volume of m=3,500 kg of water. Solving for V:

$\displaystyle V=\frac{m}{\rho}$

$\displaystyle V=\frac{3,500}{1,000}$

$V=3.5\ m^3$

The volume of water is 3.5 cubic meter

5 0

2 years ago

Choose the sequence of energy forms that best fits each item.

levacccp [35]

Answer:

1. chemical energy --> electrical energy --> light energy

2. Electrical Energy --> Mechanical Energy

3. Electrical Energy --> Heat Energy

4. Chemical Energy --> Thermal Energy --> Mechanical Energy

5. Nuclear Energy --> Light energy and thermal energy

6. Mechanical Energy --> Electric Energy

7. Chemical Energy --> Electrical Energy --> Sound Energy

8. Mechanical Energy --> Sound Energy

Explanation:

1.FLASHLIGHT:

chemical energy --> electrical energy --> light energy

The chemical energy from the cell batteries is converted to electrical energy, which is used to produce the light energy in form of flashlight.

2.ELECTRIC SAW:

Electrical Energy --> Mechanical Energy

The electrical energy from the socket is converted to the mechanical energy used to run the saw blade.

3.TOASTER:

Electrical Energy --> Heat Energy

The electrical energy from the socket is converted to the heat energy (thermal energy) used in browning the bread.

4.GAS POWERED SCOOTER:

Chemical Energy --> Thermal Energy --> Mechanical Energy

The chemical energy from fuel, such as petrol is converted to heat (thermal energy) in the engine by the process of combustion. This heat is then used to do work by conversion into mechanical energy, through piston movement, which in turn moves the shaft and the scooter.

5.THE SUN:

Nuclear Energy --> Light energy and thermal energy

The nuclear reactions on Sun provide nuclear energy which is converted into light and thermal energy that reaches us on earth.

6.WIND TURBINE:

Mechanical Energy --> Electric Energy

The mechanical energy is provided by wind when it rotates the blade of turbine. This is then converted to electrical energy b the turbine.

7.IPOD:

Chemical Energy --> Electrical Energy --> Sound Energy

The chemical energy i supplied by the battery of ipod, which is converted to electrical energy and that electrical energy is used to produce sound by ipod.

8.SPEAKER VIBRATES

Mechanical Energy --> Sound Energy

The mechanical energy due to vibration produces sound energy.

6 0

2 years ago

Read 2 more answers

if the emission lines in the spectrum of one object are more strongly blueshifted than those from a second object, then the firs

Lelu [443]

Answer:

Toward us faster than the second object

Explanation:

6 0

2 years ago

Two point charges are placed on the x axis.The firstcharge, q1= 8.00 nC, is placed a distance 16.0 mfromthe origin along the pos

deff fn [24]

Answer:

E = (0, 0.299) N

Explanation:

Given,

Charge $q_1\ =\ 8.0\ nC$
Charge $q_2\ =\ 6.0\ nC$
Distance of the first charge from the origin = (16m, 0)
Distance of the second charge from the origin = (-9, 0)
Point where the electric field required = (0, 12m)

Let $\theta_1\ and\ theta_2$ be the angle of the electric fields by first and second charge at the point A.

$\therefore sin\theta_1\ =\ \dfrac{12}{20}\\\Rightarrow \theta_1\ =\ sin^{-1}\left (\dfrac{12}{20}\ \right )\\\Rightarrow \theta_1\ =\ 36.87^o\\\\\therefore sin\theta_1\ =\ \dfrac{12}{9}\\\Rightarrow \theta_1\ =\ sin^{-1}\left (\dfrac{12}{9}\ \right )\\\Rightarrow \theta_1\ =\ 53.13^o\\$

Electric field by charge $q_1$ at point A,

$F_1\ =\ \dfrac{kq_1}{r_1^2}\\\Rightarrow F_1\ =\ \dfrac{9\times 10^9\times 8\times 10^{-9}}{20^2}\\\Rightarrow F_1\ =\ 0.18\ N/C$

Electric field by the charge $q_2$ at point A,

$F_1\ =\ \dfrac{kq_1}{r_1^2}\\\Rightarrow F_1\ =\ \dfrac{9\times 10^9\times 6.0\times 10^{-9}}{16^2}\\\Rightarrow F_1\ =\ 0.24\ N/C$

Now,

Net electric field in horizontal direction at point A $F_x\ =\ F_{1x}\ +\ F_{2x}\\\Rightarrow F_x\ =\ F_1cos\theta_1\ +\ F_2cos\theta_2\\\Rightarrow F_x\ =\ 0.18\times( -cos36.87^o)\ +\ 0.24\times cos53.13^o\\\Rightarrow F_x\ =\ -0.144\ +\ 0.144\ N/C\\\Rightarrow F_x\ =\ 0\ N/C$

Net electric field in vertical direction at point A.

$F_y\ =\ F_{1y}\ +\ F_{2y}\\\Rightarrow F_y\ =\ F_1sin\theta_1\ +\ F_2sin\theta_2\\\Rightarrow F_y\ =\ 0.18\times sin36.87^o\ +\ 0.24\times sin53.13^o\\\Rightarrow F_y\ =\ 0.180\ +\ 0.192\\\Rightarrow F_y\ =\ 0.299\ N/C$

Hence, the net electric field at point A,

$F\ =\ ( 0, 0.299 )\ N/C.$

5 0

3 years ago