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marishachu [46]
2 years ago
15

A rectangular prism has a width of 2/3 inches, a length of 5/7 inches, and a height of 9/12 inches. What is the volume of the re

ctangular prism?
Mathematics
1 answer:
balandron [24]2 years ago
5 0

Answer:

125 is the recangular prism

Step-by-step explanation:

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(4w-3)^2<br> what would be the answer to that?? please explain, i’m so confused.
yarga [219]

Answer:

16w^2  - 24w + 9

Step-by-step explanation:

To simplify this, you would use the special product (a - b)^2 = a^2 - 2ab + b^2. We can correlate this with the given term so that,

a = 4w

and

b = 3

Now we just substitute into a^2 - 2ab + b^2

(4w)^2 - 2(4w)(3) + (3)^2

16w^2  - 24w + 9

7 0
3 years ago
Read 2 more answers
Solve 6 sin((π/5)x)=5 for the four smallest positive solutions
cupoosta [38]

Answer:

1.568, 3.432, 11.568, 13.432

Step-by-step explanation:

Divide equation 6\sin\left(\dfrac{\pi }{5}x\right)=5 by 6:

\sin\left(\dfrac{\pi }{5}x\right)=\dfrac{5}{6}.

Then

\dfrac{\pi }{5}x=(-1)^k\arcsin\left(\dfrac{5}{6}\right)+\pi k,\ k\in Z,

x=(-1)^k\dfrac{5}{\pi }\arcsin\left(\dfrac{5}{6}\right)+5k,\ k\in Z.

Since \arcsin\left(\dfrac{5}{6}\right)\approx 56^{\circ}\approx \dfrac{\pi }{3.2},

four smallest positive solutions are

1. \dfrac{5}{3.2}\approx 1.568,\ k=0;

2. \dfrac{-5}{3.2}+5\approx 3.432,\ k=1;

3. \dfrac{5}{3.2}+10\approx 11.568,\ k=2;

4. \dfrac{-5}{3.2}+15\approx 13.432,\ k=3.

3 0
3 years ago
Which of the following is equivalent to the complex number i^13
mestny [16]

Answer:i

Step-by-step explanatio

4 0
3 years ago
Help please will give brainliest
ser-zykov [4K]
40=1.5f+2.25c, please mark brainiest and give it a heart (:
7 0
2 years ago
Write using exponents
gayaneshka [121]

Answer:

the first one to solve for x is  x=22-y

the first one to solve for y is y=22-x

the second one to solve for x is x=6+y

the second one to solve for y is y=-6+x

Step-by-step explanation:

in the first two you had to subtract y from both sides  of the equation

the second one you had to add y to both sides of the equation to solve for x

but to solve for y you have to move all terms that dont contain y  to the right side and solve

5 0
2 years ago
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