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2 years ago

Find the equation of the line that passes through (1,2) and is perpendicular to

Mathematics

1 answer:

uysha [10]2 years ago

3 0

Answer:

Remember that the slope of perpendicular lines are negative reciprocals of each other.

Step-by-step explanation:

y = 1 - 2x the slope is -2 the value of the x term.

So the slope of the new line using point (- 1, 2) is 1/2.

Now use y = mx + b where y = -1, x = 2, and m = 1/2 .

y = mx + b

-1 = 1/2(2) + b solve for "b", the y-intersect

-1 = 1 + b

-2 = b

The line that is perpendicular to y = 1 - 2x is y = 1/2x - 2

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3 years ago

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Semmy [17]

Answer:

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Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

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Simplifying the third term

5( $(a^p+r)^{p-r}$

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Performing the division, that is

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