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eduard
3 years ago
13

Write the equation in standard form. y + 4 = -12/7 (x - 1)

Mathematics
1 answer:
-BARSIC- [3]3 years ago
7 0

Answer:

7y+12x=-16

y-step explanation:

Multiply everything by 7 to get rid of the fractions.

Distribute the 12 into (x-1)

Then subtract 28 from the 12

Finally add the 12x over

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Simplify -3/4 ÷ 2/-8. (1 point)
Katarina [22]

Answer:

=3/1 or 3

Step-by-step explanation:

-3/4÷2/-8

=-3 × -8/4 × 2

=24/8

=24 ÷ 8/8 ÷ 8

=3/1

5 0
4 years ago
Consider two unique parallel lines. what aspects of these two lines are the same? what aspects of these two lines would have to
kramer

If you have edunuity, the answer is... Two parallel lines will have the same slope. The slopes of parallel lines have to be equal. The y-intercepts of those two lines have to be different, otherwise they would be the same line. The x-intercepts of the parallel lines would also be different.

8 0
3 years ago
Read 2 more answers
HELP ME I NEED HELLLPPP I AM A 6th grater if u ask HELLLPP ME
Ulleksa [173]

Answer:

Multiply by 3;9

Step-by-step explanation:

9/3=3

12/4=3

18/6=3

27/n=3

N=9

8 0
4 years ago
What is the inverse of f (x)=10-×^2
Bad White [126]
Finding the inverse function of

\mathsf{f(x)=10-x^2}


Remember that when you compose f with its inverse \mathsf{f^{-1}}, you'll get the identity function:

\mathsf{(f\circ f^{-1})(x)=x}\\\\ \mathsf{f\big[f^{-1}(x)\big]=x}\\\\


So if

\mathsf{f(x)=10-x^2}


then

\mathsf{f\big[f^{-1}(x)\big]=10-[f^{-1}(x)]^2}\\\\ \mathsf{x=10-[f^{-1}(x)]^2}\\\\ \mathsf{[f^{-1}(x)]^2=10-x}\\\\ \mathsf{f^{-1}(x)=\pm \sqrt{10-x}}\\\\ \mathsf{f^{-1}(x)=-\sqrt{10-x}~~~or~~~f^{-1}(x)=\sqrt{10-x}}


The sign of the inverse depends on the domain of \mathsf{f(x)} itself, and where it's invertible.


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2198197


I hope this helps.


Tags: <em>inverse function definition identity domain algebra</em>

3 0
3 years ago
Determine the lateral area of a pipe that is 12 ft long and 25 ft in diameter.
Zina [86]

Answer:

The lateral area of the pipe is 942 sq ft.

Step-by-step explanation:

A pipe can be modeled as a cylinder prism.

The lateral area of a cylinder prism can be expressed as the product of the length by the perimeter of the section.

We start by calculating this perimeter.

As the diameter is 25 ft, the perimeter of the section can be expressed as:

P=\pi D=3.14\cdot 25=78.5

Then, to know the lateral surface we multiply this perimeter by the length of the pipe (12 ft):

A=P\cdot l=78.5\,ft\cdot 12\,ft=942\,ft^2

The lateral area of the pipe is 942 sq ft.

8 0
4 years ago
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