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2 years ago

HELP QUICK! PLEASE! PLEASE!

Mathematics

2 answers:

Alex787 [66]2 years ago

5 0

Answer:

I dont know

Step-by-step explanation:

You always do something with the multiplication and division.

Solnce55 [7]2 years ago

5 0

Answer:

9 + 3 x ( 2 ^2 - 1 ) x 4 = 45

Step-by-step explanation:

1: 2x2 - 1 = 3

2: 9 + 3 x 3 x 4 = 45

3: 9 + 9 x 4 = 45

To change the value of expression to 45 we need to put the parentheses in front 2 and after 1.

Don't forget the order of operation.

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Which rows represent when (p ∧ q) ∨ (p ∧ r) is true?\

tatyana61 [14]

<span>the statement is ambiguous, it must be written as (p ∧ q) ∨ r
or p ∧ (q ∨ r).</span>

8 0

3 years ago

If a radius of a circle is 12 feet, what is the area and perimeter of the circle?

Vesna [10]

Area of a circle=πr²
area of this cirlce=π*(12 ft)²=144π ft²≈452.39 ft².

answer 1= the area of this circle is 452.39 ft².

Perimeter of a circle=2πr.
Perimeter of this cirlce=2π(12 ft)=24π ft≈75.4 ft

<span>answer 2= the perimeter of this cirlce is 75.4 ft.</span>

4 0

3 years ago

Read 2 more answers

How do you solve this equation?

Natasha2012 [34]

Answer:

$5 \sqrt{2}$

= 7.071067812

Step-by-step explanation:

hope this helps

8 0

2 years ago

Hi im having troble cobineing like terms -10a - 9n + 16 - 30 + 3n + 15a + 50 + a

goldenfox [79]

Answer:

6a-6n+36

Step-by-step explanation:

-10a-9n+16-30+3n+15a+50+a

Combine a...

-10a+15a= 5a+a=6a

Combine n...

6a-9n+16-30+3n+50

-9n+3n= -6n

6a-6n+ 16-30+50

Combine # w no variable

Answer: 6a-6n+36

5 0

3 years ago

Read 2 more answers

A sphere of radius r is cut by a plane h units above the equator, where

Anika [276]

Consider the top half of a sphere centered at the origin with radius $r$ , which can be described by the equation

$z=\sqrt{r^2-x^2-y^2}$

and consider a plane

$z=h$

with $0$ . Call the region between the two surfaces $R$ . The volume of $R$ is given by the triple integral

$\displaystyle\iiint_R\mathrm dV=\int_{-\sqrt{r^2-h^2}}^{\sqrt{r^2-h^2}}\int_{-\sqrt{r^2-h^2-x^2}}^{\sqrt{r^2-h^2-x^2}}\int_h^{\sqrt{r^2-x^2-y^2}}\mathrm dz\,\mathrm dy\,\mathrm dx$

Converting to polar coordinates will help make this computation easier. Set

$\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\var\phi\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi$

Now, the volume can be computed with the integral

$\displaystyle\iiint_R\mathrm dV=\int_0^{2\pi}\int_0^{\arctan\frac{\sqrt{r^2-h^2}}h}\int_{h\sec\varphi}^r\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$

You should get

$\dfrac{2\pi}3\left(r^3\arctan\dfrac{\sqrt{r^2-h^2}}h-\dfrac{h^3}2\left(\dfrac{r\sqrt{r^2-h^2}}{h^2}+\ln\dfrac{r+\sqrt{r^2-h^2}}h\right)\right)$

5 0

3 years ago