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3 years ago

Predict which atom has the higher ionization energy. Na Al

1 answer:

8 0

1st ionizaton energy has a trend from down to up and from left to right. Since Na and Al are on the same period (row), then the we look at which is the the furthest to the right and that would be Al.

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Which type of storm is measured by the fujita scale?

Serggg [28]

It's used for the intensity of a tornado

3 0

3 years ago

Read 2 more answers

a constant current of 3 a for 4 hours is required to charge an automotive battery.if the terminal voltage is 10 t/2 v, where t i

Korvikt [17]

The charge transported as a result of charging is 43200C .

we can note the following data from the statement :

Current (i) = 3A

Time interval (t) = 4 hrs = 14400secs

As we know ,

Current is defined as the rate of flow of the charges between two points when a potential difference is applied between them.

Mathematically , it can be written as

Current(i) = charge (q)/ time(t)

Q = i × t

= 3 × 14400

= 43200 C

By dividing the value of the current passed through the circuit by the time for which the charge is passed gives out the value of the charge passed .

learn more on charges :

brainly.com/question/15238352

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3 0

1 year ago

Convert 2536 mm/min to m/s. Use dimensional analysis.

Deffense [45]

Answer:

As we know that, 

1 mm/min = 1.66667E-5 m/s
1 m/s = 60000 mm/min

Now, come to the question - 

$\\ \implies \sf \: 2536 \times 1.66667E-5 m/s \\ \\ \\ \implies \sf \blue{0.0422666667 \:m/s } \\$

Result : 2536 mm/min = 0.0422666667 m/s.

6 0

4 years ago

Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference between its te

alexgriva [62]

Answer:

4.9 minutes

Explanation:

Given; T(t) = Ce^-kt + Ts

Now;

T(t) = 190 degrees Fahrenheit

Ts = 60 degrees

To obtain C;

190 = Ce^0 + 60

190 - 60 = C

C = 130

Hence, to find k when t=11

172 = 130 e^-11k + 60

172 -60/130 = e^-k

e^-k = 0.86

ln(e^-k) = ln( 0.86)

-k = -0.15

k = 0.15

Hence at 122 degrees, t is;

T(t) = Ce^-kt + Ts

122 = 130e^-0.15t + 60

122 - 60/130 = e^-0.15t

0.477 = e^-0.15t

ln (e^-0.15t) = ln (0.477)

-0.15t = -0.74

t = 0.74/0.15

t = 4.9 minutes

5 0

3 years ago

What would an automobile engineer MOST LIKELY suggest to improve the efficiency of a car's engine? A) Remove the engine's coolin

TiliK225 [7]

Answer:

D) Reduce the internal friction of the engine's parts.

Explanation:

To increase the efficiency of the car's engine, an engineer most like has to reduce the friction within the internal engine parts. Reducing these friction reduces the useful energy lost as heat in these internal parts of the engine, when the engine parts do work against friction to move. In most everyday activities, engines and machines, energy is usually lost as heat due to frictional forces arising from two or more surfaces in contact.

3 0

4 years ago