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3 years ago

How many Americans get sick from consuming contaminated food/water each year

Physics

2 answers:

Gnoma [55]3 years ago

3 0

Answer:

48 million people get sick, 128,000 are hospitalized, and 3,000 die

Explanation:

mixer [17]3 years ago

3 0

Answer:

48 million is get sick from consuming contaminated food/water each 6ear

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If an X-ray tube is operating at a current of 30.0 mA:a) How many electrons are striking the target per second? b) If the potent

Zina [86]

Answer:

Explanation:

A. Q= It

30E-3A=q

Ne = q

30E-3/1.6*10-19= N

N= 1.8*10^16 electrons

B. Power= I x v

= 30*10^-3A x 100*10^3v

= 3000watts

3 0

3 years ago

A water discharge of 9 m3/s is to flow through this horizontal pipe, which is 0.98 m in diameter. If the head loss is given as 1

Mashutka [201]

Answer: The power required by the pump to produce a discharge of 9m³/s is 5990joules/secs.

Explanation: The given parameters from the questions are:

Flow rate Q = 9m³/s, Diameter D = 0.98m, acceleration a = 1.0, head loss(Pressure P) is given by the function 10v²/2g.

STEP 1. Find the velocity of water in the pipe from the equation:

Diameter D = (√4.Q/π.v), where v is the velocity, and Q is flow rate

Making v subject of the formula gives:

v = 4Q/π.√D =[ 4 × 9m³/s / 3.142 × (√0.98m)] = 11.69m/s.

STEP 2. Find the pressure from the relationship, P = 10v²/2g, NB. g = a

P = 10 × (11.69m/s)² / 2× 1.0m/s²

P = 683.25N/m² or Pascal.

STEP 3. Find force exerted by the pump;

Recall that Pressure P = Force/Area

But Area A = π.r², where r = D/2

Therefore, A = π.(D/2)²

A = 3.142 × [0.98m/2]² = 0.75m²

Therefore, Force = Pressure × Area

Force F = 683.25N/m² × 0.75m²

F = 512.44N.

STEP 4. Find work done

Work done W by the pump is = Force × distance d moved by the water

W = F . d

Also recall that flow rate Q = Velocity/time.

Q = v/t, we can write t = v/Q.

Time t = 11.69m/s / 9m³/s = 1.298s

Also recall that velocity v = distance d/time t, v = d/t, making d subject of formula gives v × t

Distance d = v × t = 11.69m/s × 1.298s = 15.17m.

Hence,

Work Done W = Force × distance

W = 512.44N × 15.17m = 7775.56Nm or joules.

Lastly, Power P = Work done/ time

P = 7775.56joules/1.298s

P = 5990.4joules/s.

8 0

2 years ago

Two long current-carrying wires run parallel to each other and are separated by a distance of 5.00 cm. If the current in one wir

Darya [45]

Answer:

The magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.

Explanation:

Given;

distance between the parallel wires, r = 5.0 cm = 0.05 m

current in the first wire, I₁ = 1.65 A

current in the second wire, I₂ = 3.25 A

The magnitude of the force per unit length between the two wires is calculated as follows;

$\frac{F}{l} =\frac{\mu_0 I_1 I_2}{2\pi r} \\\\\frac{F}{l} =\frac{4\pi \times 10^{-7} \times 1.65 \times 3.25}{2\pi \times 0.05} \\\\\frac{F}{l} = 2.145 \times 10^{-5} \ N/m$

Therefore, the magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.

5 0

3 years ago

A 50 kg woman, riding on a 10 kg cart, is moving east at 5.0 m/s. the woman jumps off the cart and hits the ground running at 7.

pav-90 [236]

To answer this question, we will use the law of conservation of momentum which states that:
(m1+m2)Vi = m1V1 + m2V2 where:
m1 is the mass of the woman = 50 kg
m2 is the mass of the cart = 10 kg
Vi is the initial velocity (of woman and cart combined) = 5 m/sec
V1 is the final velocity of the woman = 7 m/sec
V2 is the final velocity of the cart that we need to calculate

Substitute with the givens in the above equation to get the final velocity of the cart as follows:
(50+10)(5) = (50)(7) + (10)V2
10V2 = -50
V2 = -5 m/sec
Note that the negative sign indicates that the cart is moving in an opposite direction to the others.

4 0

3 years ago

A gas storage cylinder in an ordinary chemical laboratory measures wide and high. This is the label on it. Contents: gas Pressur

zhenek [66]

Complete Question

A gas storage cylinder in an ordinary chemical laboratory measures 3.5 cm wide and 9.2 cm high with this label on it:

Contents: N2 Gas

Pressure 18.6 atm

If the cylinder is opened and the gas allowed to escape into a large empty plastic bag, what will be the final volume of nitrogen gas, including what’s collected in the plastic bag and what’s left over in the cylinder?

Use 1 atm for the gas final pressure

Answer:

The final volume is 1647.03cm³ or 1.65 litres

Explanation:

Given

Width of cylinder, W = 3.5 cm

Height of Cylinder, H = 9.2 cm

Gas Initial Pressure, P1 = 18.6 atm

Gas Final Pressure, P2 = 1 atm

First, the initial volume of gas has to be calculated to known the quantity of gas before gas outflow

Volume of Gas, V = Volume of a cylinder

V = πr²h

Given the the width of the cylinder is 3.5cm

This means that the diameter of the cylinder is also 3.5cm

Hence; Diameter, D = 3.5cm

Radius, r = ½D

r = ½ * 3.5cm

r = 1.75cm

So, V1 = πr²h becomes

V1 = π * 1.75² * 9.2

V1 = 28.175π cm³

V1 = 88.55 cm³

From Ideal Gas Law;

PV = nRT

Where k = PV (From Boyle's Law)

P1V1 = P2V2 ---- Make V2 the subject of formula

V2 = (P1V1)/P2

Where P1,P2,V1 and V2 represent the initial pressure, final pressure, initial volume and final volume, respectively.

Recall that P1 = 18.6 atm

P2 = 1 atm

V1 = 88.55 cm³

Final volume, V2 = (P1V1)/P2

V2 = (18.6 atm * 88.55 cm³)/1 atm³

V2 = 1647.03cm³

Convert to Litre

V2 = 1647.03/1000

V2 = 1.64703 litres

V2 = 1.65 L

Hence, the final volume is 1647.03cm³ or 1.65litres

8 0

3 years ago