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Aneli [31]
2 years ago
13

As you move upward, from level, in an energy pyramid, available energy ____.

Chemistry
1 answer:
svetlana [45]2 years ago
8 0

The available energy decreases as one moves upward in an energy pyramid.

<h3>Energy pyramid</h3>

The energy pyramid represents a model of how energy is transferred from one trophic level to another in ecosystems.

Energy is transferred from producers to primary consumers, from primary to secondary consumers, from secondary to tertiary consumers, and so on.

Only about 10% of the available energy in one trophic level is transferred to the next with the remaining 90% being lost as heat to the environment.

Thus, as one moves up the energy pyramid, the available energy decreases. This is why organisms at the higher end of the energy pyramid have to devise an efficient way of extracting energy from their foods.

More on energy pyramid can be found here: brainly.com/question/2515928

#SPJ1

You might be interested in
If it takes 2000 years to weather 1 cm of limestone, how long will it take to weather 5 cm of limestone?
Anna71 [15]

Answer:10,0000 years

Explanation:

If it takes 2000 years to weather 1cm of limestone

It will take 5*2000 years to weather 5cm of limestone. This gives us 10000 years.

3 0
3 years ago
To what temperature does a 250 ml cylinder containing 0.40 grams of helium gas need to be collected in order for the pressure to
VMariaS [17]

Answer:

T =76.13 K

Explanation:

Given data:

Temperature of gas = ?

Volume of gas = 250 mL(250/1000 = 0.25 L)

Mass of helium = 0.40 g

Pressure of gas = 253.25 kpa (253.25/101 = 2.5 atm)

Solution:

Formula:

PV = nRT

First of all we will determine the number of moles of helium.

Number of moles = mass/ molar mass

Number of moles = 0.40 g/ 4 g/mol

Number of moles = 0.1 mol

Now we will put the values.

R = general gas constant = 0.0821 atm.L/ mol.K

T = PV/nR

T =2.5 atm× 0.25 L /0.1 mol ×0.0821 atm.L/ mol.K

T = 0.625  /0.00821/K

T =76.13 K

6 0
3 years ago
Suppose the reaction between nitrogen and hydrogen was run according to the amounts presented in Part A, and the temperature and
andrew11 [14]

Explanation:

Assuming that moles of nitrogen present are 0.227 and moles of hydrogen are 0.681. And, initially there are 0.908 moles of gas particles.

This means that, for N_{2}(g) + 3H_{2}(g) \rightarrow 2NH_{3}

 moles of N_{2} + moles of H_{2} = 0.908 mol

Since, 2 moles of N_{2} = 2 \times 0.227 = 0.454 mol

As it is known that the ideal gas equation  is PV = nRT

And, as the temperature and volume were kept constant, so we can write

        \frac{P(_in)}{n_(in)} = \frac{P_(final)}{n_(final)}

          \frac{10.4}{0.908} = \frac{P_(final)}{0.454&#10;}

       P_(final) = 10.4 \times \frac{0.454}{0.908}

                            = 5.2 atm

Therefore, we can conclude that the expected pressure after the reaction was completed is 5.2 atm.

7 0
2 years ago
the isotope of an atom containing 31 protons and 39 neutrons suddenly has two neutrons added to it. what isotope is created? a.
olasank [31]
The elements are identified by the number of protons of the atom, which is its atomic number.

In this case the number of protons 39 (atomic number 39) permit you to identify the element as gallium.

Now, to identify the isotope you tell the name of the element and add the mass number.

The mass number is the sum of the protons and the neutrons

In this case, the number of neutrons is the original 39 plus the 2 added suddenly, i.e. 39 + 2 = 41, so the mass number is 31 + 41 = 72

Therefore, the isotope is gallium - 72.

Answer: isotope gallium - 72

7 0
2 years ago
Read 2 more answers
Please with this problem
olasank [31]
<h3>Answer:</h3>

            Empirical Formula  =  C₃H₈O₃

            Molecular Formula  =  C₃H₈O₃

<h3>Solution:</h3>

Data Given:

                      Mass of Sample  =  9.2 g

                      Mass of Carbon  =  3.6 g

                      Mass of Hydrogen  =  0.8 g

                      Mass of Oxygen  =  9.2 - (3.6 + 0.8) = 4.8 g

Step 1: Calculate Moles of each Element;

                      Moles of C  =  Mass of C ÷ At.Mass of C

                      Moles of C  = 3.6 ÷ 12.01

                      Moles of C  =  0.2997 mol


                      Moles of H  =  Mass of H ÷ At.Mass of H

                      Moles of H  = 0.8 ÷ 1.01

                      Moles of H  =  0.7920 mol


                      Moles of O  =  Mass of O ÷ At.Mass of O

                      Moles of O  = 4.8 ÷ 16.0

                      Moles of O  =  0.3000 mol

Step 2: Find out mole ratio and simplify it;

                C                                        H                                     O

            0.2997                              0.7920                           0.3000

    0.2997/0.2997                  0.7920/0.2997              0.3000/0.2997

               1                                      2.64                                    1.001

Multiply by 3,

               3                               7.92 ≈ 8                                    3

Hence,  Empirical Formula  =  C₃H₈O₃

Step 3: Calculating Molecular Formula:

Molecular formula is calculated by using following formula,

                    Molecular Formula  =  n × Empirical Formula  ---- (1)

Also, n is given as,

                     n  =  Molecular Weight / Empirical Formula Weight

Molecular Weight  =  92 g.mol⁻¹

Empirical Formula Weight  =  12 (C₃) + 1.01 (H₈) + 16 (O₃)  =  92.08 g.mol⁻¹

So,

                     n  =  92 g.mol⁻¹ ÷ 92 g.mol⁻¹

                     n  =  1

Putting Empirical Formula and value of "n" in equation 1,

                    Molecular Formula  = 1 × C₃H₈O₃

                    Molecular Formula  =  C₃H₈O₃

7 0
2 years ago
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