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grigory [225]
4 years ago
6

PLEASE HELP ME WITH A PHYSICS QUESTION!!!!!!!!!!

Physics
2 answers:
stira [4]4 years ago
6 0

Answer:

C. 3.00 s

Explanation:

Given:

Δy = 1.80 m − 46.0 m = -44.2 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

-44.2 m = (0 m/s) t + ½ (-9.8 m/s²) t²

t = 3.00 s

vodomira [7]4 years ago
5 0

Answer:

C. 3.00 s

Explanation:

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Answer:

I do not think that it is the most reliable way to gain information since it is very hard to do and can be easily messed up. No, I don't think you can charge someone on only evidence from blood spatter, but if there was additional evidence I think that this would definitely help with the case but not on its own, since it doesn’t give you physical evidence about the suspect.

Explanation:

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3 years ago
A sound wave with a frequency of 400 Hz is moving through a solid object. If the wavelength of the sound wave is 8 m, what is th
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Answer:

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3 years ago
What is the half-reaction that occurs at the cathode during the electrolysis of molten potassium bromide?
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The complete ionization of KBr into its constituents is:<span>
<span>KBr (s)  --->  K+ (aq)  +  Br- (aq)</span></span>

<span>
During electrolysis, oxidation takes place at the anode electrode. This means that an ion is stripped off its electron hence becoming more positive:
<span>2 Br- (aq)  --->  Br2 (g) + 2e- </span></span>

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<span>
<span>Meanwhile at the cathode, the reduction reaction occurs. Which means that the electron from the anode electrode is used to make an ion more negative:
<span>2K+ (aq)  +  2e-  --->  2K (s) </span></span>
Hence, through reduction, solid potassium is deposited on the plate.</span>

 

 

Half reactions:

<span>Anode: 2 Br- (aq)  --->  Br2 (g) + 2e- </span>                       

<span>Cathode: 2K+ (aq)  +  2e-  --->  2K (s) </span>

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The correct answer is B the total velocity is equal at both landing and launch because before your about launch you have 0 velocity then when you have landed you also have 0 velocity. Hope This Helps

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3 years ago
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