A charged particle moving in a magnetic field experiences a force equal to:
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Thus, the magnitude of the force that the proton experiences is given by:
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The magnetic field is perpendicular to the proton's velocity, therefore, we have
. Replacing the given values, we obtain:
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Answer:
the first one is energy level
Explanation:
B.) <span>The amp is the unit for "Current"
Hope this helps!</span>
AS
work done =W = F.d = F d cosФ (Ф is angle between force F and displacement d) If a body/object is moving on a smooth surface (friction-less surface ) .There is no force acting on that body. F=0 so W=FdcosФ= (0)dcosФ ⇒ W=0
Now if a body is facing some amount of force but under the action of force there is no displacement covered. d=0 so W =FdcosФ= F(0)cosФ ⇒W=0
example: A person is applying a force on rigid wall but wall remains at rest there is no displacement occurs in wall.
The third term upon which work done dependent is angle between force and displacement i.e Ф. If Ф=90° then W= FdcosФ= Fdcos90⇒ W=0 ( as cos 90°=0)