We have vector ![(17.9*cos80^{0},17.9*sin80^{0})](https://tex.z-dn.net/?f=%2817.9%2Acos80%5E%7B0%7D%2C17.9%2Asin80%5E%7B0%7D%29)
Therefore,
x component = 17.9 * cos80 degree = 3.108
y component = 17.9 * sin80 degrees = 17.628
<h3>What is a vector?</h3>
An object with both magnitude and direction is referred to be a vector. A vector can be visualized geometrically as a directed line segment, with an arrow pointing in the direction and a length equal to the magnitude of the vector. The vector points in a direction from its tail to its head.
If the magnitude and direction of two vectors match, they are the same vector. This shows that if we move a vector to a different location without rotating it, the final vector will be the same as the initial vector. The vectors that denote force and velocity are two examples. The direction of force and velocity are both fixed. The size of the vector would represent the force's strength or the velocity's corresponding speed.
To know more about vectors, visit:
brainly.com/question/12937011
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Answer:
Proton, stable subatomic particle that has a positive charge equal in magnitude to a unit of electron charge and a rest mass of 1.67262 × 10−27 kg, which is 1,836 times the mass of an electron.
Answer:
it's false coz
Speed is a scalar quantity.
That latest value for the Angle is in Grads, not in Kilograms.
Apply law of conservation of momentum along vertical direction.
![m_1v_1sin\theta_1-m_2v_2sin\theta_2=0](https://tex.z-dn.net/?f=m_1v_1sin%5Ctheta_1-m_2v_2sin%5Ctheta_2%3D0)
![v_2=\frac{v_1sin\theta_1}{sin\theta_2}=\frac{sin54}{sin36}v_1 = 1.376v_1](https://tex.z-dn.net/?f=v_2%3D%5Cfrac%7Bv_1sin%5Ctheta_1%7D%7Bsin%5Ctheta_2%7D%3D%5Cfrac%7Bsin54%7D%7Bsin36%7Dv_1%20%3D%201.376v_1)
Apply law of conservation of momentum along the horizontal direction
![m_1u_1=m_1v_1cos\theta_1+m_2v_2cos\theta_2](https://tex.z-dn.net/?f=m_1u_1%3Dm_1v_1cos%5Ctheta_1%2Bm_2v_2cos%5Ctheta_2)
![u_1=v_1(cos\theta_1+1.376cos\theta_2)](https://tex.z-dn.net/?f=u_1%3Dv_1%28cos%5Ctheta_1%2B1.376cos%5Ctheta_2%29)
![u_1=v_1(cos(54)+1.376cos(36))](https://tex.z-dn.net/?f=u_1%3Dv_1%28cos%2854%29%2B1.376cos%2836%29%29)
![u_1=(1.7) v_1](https://tex.z-dn.net/?f=u_1%3D%281.7%29%20v_1)
![v_1= \frac{3.14}{1.7}=1.84m/s](https://tex.z-dn.net/?f=v_1%3D%20%5Cfrac%7B3.14%7D%7B1.7%7D%3D1.84m%2Fs)
The second ball velocity is ![v_2 = (1.376)(1.84)=2.531m/s](https://tex.z-dn.net/?f=v_2%20%3D%20%281.376%29%281.84%29%3D2.531m%2Fs)
The magnitud of final total momentum is
![m(v_1+v_2)=(1.37)(2.531+1.84)=5.98kgm/s](https://tex.z-dn.net/?f=m%28v_1%2Bv_2%29%3D%281.37%29%282.531%2B1.84%29%3D5.98kgm%2Fs)
The magnitude of final energy is
![\frac{1}{2}m(v^2_1+v^2_2)=\frac{1}{2}(1.37)(2.531^2+1.84^2)=6.07J](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dm%28v%5E2_1%2Bv%5E2_2%29%3D%5Cfrac%7B1%7D%7B2%7D%281.37%29%282.531%5E2%2B1.84%5E2%29%3D6.07J)