Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
1 answer:
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Answer:
The potential difference between the plates is
Explanation:
Given that,
Distance = 1.4 mm
Electric field strength
Let the potential difference is V.
We need to calculate the potential difference between the plates
Using formula of electric field
Where, V = potential
d = distance
Put the value into the formula
Hence, The potential difference between the plates is
1 m = 1 000 000 ym
converted other way we can say that:
1 ym =
m
Now, since we have ym^2 which is ym*ym which means:
1 ym^2 =
m
we have 1,5 ym^2 which means that answer is:
converted other way we can say that:
1 ym =
Now, since we have ym^2 which is ym*ym which means:
1 ym^2 =
we have 1,5 ym^2 which means that answer is:
Explanation:
Given that,
A person walks 9.0 km directly east and then turns left and heads directly north for 12.0 km.
We need to find his displacement from the starting position.
We know that,
Displacement = shortest path covered
For direction,
Hence, this is the required solution.