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Pavel [41]
3 years ago
7

Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'

' (t) is its acceleration. x(t) = t3 − 12t2 + 21t − 9, 0 ≤ t ≤ 10 (a) Find the velocity and acceleration of the particle.
Physics
1 answer:
nignag [31]3 years ago
5 0

The position of the particle is given by:

x(t) = t³ - 12t² + 21t - 9

Differentiate x(t) with respect to t to find the velocity x'(t):

x'(t) = 3t² - 24t + 21

Differentiate x'(t) with respect to t to find the acceleration x''(t):

x''(t) = 6t - 24

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7 0
3 years ago
The intensity of the sound from a certain source is measured at two points along a line from the source. The points are separate
Artemon [7]

Answer:

The source is at a distance of 4.56 m from the first point.

Solution:

As per the question:

Separation distance between the points, d = 11.0 m

Sound level at the first point, L = 66.40 dB

Sound level at the second point, L'= 55.74 dB

Now,

L = 10log_{10}\frac{I}{I_{o}}          

I = I_{o}10^{\frac{L}{10}} = I_{o}10^{0.1L} = 10^{- 12}\times 10^{0.1\times 66.40} = 10^{- 5.36}      

L' = 10log_{10}\frac{I'}{I_{o}}

I' = I_{o}10^{\frac{L'}{10}} = 10^{- 12}\times 10^{0.1\times 55.74} = 10^{- 6.426}        

where

I_{o} = 10^{- 12} W/m^{2}

I = Intensity of sound

Now,

I = \frac{P}{4\pi R^{2}}

Similarly,

I' = \frac{P}{4\pi (R + 11.0)^{2}}

Now,

\frac{I}{I'} = \frac{(R + 11.0)^{2}}{R^{2}}

\frac{10^{- 5.36}}{10^{- 6.426}} = \frac{(R + 11.0)^{2}}{R^{2}}

R ^{2} + 22R + 121 = 11.64R^{2}}

10.64R ^{2} - 22R - 121 = 0

Solving the above quadratic eqn, we get:

R = 4.56 m

8 0
3 years ago
What is 25 degrees Celsius equal to in Fahrenheit? I need to know how to do it to, so give me a formula, and it would help if yo
andreev551 [17]
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5 0
3 years ago
Two identical parallel plate capacitors A and B connected to a battery of V volts w/ the switch S closed. The switch is now open
Basile [38]
The electrostatic energy stored in a capacitor with capacitance C_0, with a voltage difference V applied to it, and without dielectric, is given by
U_0 =  \frac{1}{2} C_0 V^2
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C_k = k C_0
So, the energy stored now is
U_k =  \frac{1}{2}C_k V^2= \frac{1}{2}kC_0 V^2

Therefore, the ratio between the energies stored in the capacitor before and after the introduction of the dielectric is
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5 0
3 years ago
Why is reaching activation energy necessary? Reactants require a minimum amount of energy to start to break a chemical bond. Pro
Ksju [112]

Answer:

<em>Reaching activation energy</em><em> is necessary because reactants require a </em><em>minimum</em><em> </em><em>amount of energy</em><em> start breaking a</em><em> chemical bond.</em>

Explanation:

Activation energy is the minimum amount of energy required by the reactants to initiate a chemical reaction. The unit of activation energy is joule or  kilo joule per mole or kilo calories per mole. Activation energy depends on temperature.

The temperature dependence of activation energy is given  by Arrhenious equation. Activation energy is a threshold value of energy. For any reaction to occur this is the minimum amount of energy required.

7 0
4 years ago
Read 2 more answers
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