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Butoxors [25]
2 years ago
8

A stationary 15 kg object is located in a table near the surface of the earth. The coefficient of static friction between the su

rfaces is 0.40 and the coefficient of kinetic friction is 0.25.
A horizontal force of 40 N is applied to the object.
Determine the acceleration of the object.
Physics
1 answer:
Marta_Voda [28]2 years ago
8 0

The net force acting on the object perpendicular to the table is

∑ F[perp] = F[normal] - mg = 0

where mg is the weight of the object. Then

F[normal] = mg = (15 kg) (9.8 m/s²) = 147 N

The maximum magnitude of static friction is then

0.40 F[normal] = 58.8 N

which means the applied 40 N force is not enough to make the object start to move. So the object has zero acceleration and does not move.

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Answer:

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Explanation:

<em>Lets explain how to solve the problem</em>

You found that the best height to pitch a water balloon in order for it to

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We consider that the 12 meters is the maximum height, so the velocity

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To find the velocity when the balloon hits the ground lets use the rule

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u = 0 , h = 12 m , g = 9.8 m/s²

<em>Substitute these values in the equation above</em>

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v = ± \sqrt{235.2}

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Then v = -15.34 m/s

<em>The balloon hit the ground with velocity -15.34 m/s</em>

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