A dog kennel owner has 121 ft of fencing to enclose a rectangular dog run. She wants it to
1 answer:
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Using a system of equation, we have that:
a)
- x, which is the cost of on-site service.
- y, which is the cost of at-store service.
- z, which is the cost of by-mail service.
b)
The system is:
c)
The cost of one on-site repair service is of $90.
Item a:
The variables are:
- x, which is the cost of on-site service.
- y, which is the cost of at-store service.
- z, which is the cost of by-mail service.
Item b:
On-site service costs <u>3 times as much as at-store service</u>, thus:
By mail service costs <u>$10 less than at-store</u> service, thus:
Last week, the shop completed <u>15 services on-site, 40 services at-store, and 5 services by mail for total sales of $3100</u>, thus:
The system is:
Item c:
- The cost of one on-site repair service is x.
- First, replacing the first two equations into the third, we find y, and then with it we find x.
Then
The cost of one on-site repair service is of $90.
A similar problem is given at brainly.com/question/24823220
Answer:
<u>630</u> MP3 players are likely to be defective.
Step-by-step explanation:
Given:
A shipment to a warehouse consists of 4500 MP3 players the manager chooses a random sample of 50 MP3 players and finds that 7 are defective.
Now, to find the MP3 players which are likely to be defective.
Let the defective MP3 players be
Total MP3 players = 4500.
In sample of 50 MP3 players 7 are defective.
Now, setting the proportion:
If, 50 is equivalent to 7.
Then, 4500 is equivalent to
Now, to solve using cross multiplication method:
<em>By cross multiplying we get:</em>
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<em>Dividing both sides by 50 we get:</em>
Therefore, 630 MP3 players are likely to be defective.