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2 years ago

Collisions covalent bonding level 16

Chemistry

1 answer:

Maru [420]2 years ago

7 0

<h2>What is collision theory in chemistry?</h2>

In chemistry, according to Collision theory: It states that for a chemical reaction to occur, the reacting particles must collide with one another. The rate of the reaction depends on the frequency of collisions. The theory also tells us that reacting particles often collide without reacting.

There are two kinds of ions that are cation and anion. The former type is formed by metal by the loss of electrons whereas the latter type is formed by non-metal by the gain of electrons.

Group 16 of the periodic table contains the elements whose symbols are O, S, Se, Te, and Po. The generalized configuration of electrons in the nth...

Therefore, these elements will gain two electrons and become stable by achieving an inert gas configuration that is nearest to them. Thus, group 16 elements will form ions with a charge of -2.

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Molar mass of 34.00 g/mol molecular formula

alukav5142 [94]

Multiplying the subscripts within the empirical formula by this number gives you the molecular formula H2O2.

8 0

4 years ago

Which subshells (s, p, d, f, or g) can have electrons with the indicated magnetic quantum number (ml)?

amm1812

Answer:

=3 means is 3 or greater so that would be f and g subshells

=0 means is 0 or greater so that would be s, p, d, f and g subshells

=1 means is 1 or greater so that would be p, d, f, and g subshells

=4 means is 4 or greater so that would be g only

4 0

2 years ago

A 3.50 g sample of an unknown compound containing only C , H , and O combusts in an oxygen‑rich environment. When the products h

statuscvo [17]

Explanation:

First, calculate the moles of $CO_{2}$ using ideal gas equation as follows.

PV = nRT

or, n = $\frac{PV}{RT}$

= $\frac{1 atm \times 4.41 ml}{0.0821 Latm/mol K \times 293 K}$ (as 1 bar = 1 atm (approx))

= 0.183 mol

As, Density = $\frac{mass}{volume}$

Hence, mass of water will be as follows.

Density = $\frac{mass}{volume}$

0.998 g/ml = $\frac{mass}{3.26 ml}$

mass = 3.25 g

Similarly, calculate the moles of water as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{3.25 g}{18.02 g/mol}$

= 0.180 mol

Moles of hydrogen = $0.180 \times 2$ = 0.36 mol

Now, mass of carbon will be as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

0.183 mol = $\frac{mass}{12 g/mol}$

= 2.19 g

Therefore, mass of oxygen will be as follows.

Mass of O = mass of sample - (mass of C + mass of H)

= 3.50 g - (2.19 g + 0.36 g)

= 0.95 g

Therefore, moles of oxygen will be as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{0.95 g}{16 g/mol}$

= 0.059 mol

Now, diving number of moles of each element of the compound by smallest no. of moles as follows.

C H O

No. of moles: 0.183 0.36 0.059

On dividing: 3.1 6.1 1

Therefore, empirical formula of the given compound is $C_{3}H_{6}O$ .

Thus, we can conclude that empirical formula of the given compound is $C_{3}H_{6}O$ .

6 0

3 years ago

How can you tell S-wave arrival from the end of the P-wave?

Margarita [4]

Answer:

<h2>The P wave will be the first wiggle that is bigger than the rest of the little ones (the microseisms). Because P waves are the fastest seismic waves, they will usually be the first ones that your seismograph records. The next set of seismic waves on your seismogram will be the S waves</h2>

4 0

3 years ago

In this chemical reaction, how many grams of h2 will react completely with6.50 moles of CO

geniusboy [140]

52 g of hydrogen H₂

Explanation:

I will assume that the problem is talking about the hydrogenation of carbon dioxide CO₂ not carbon monoxide CO. It is harder to reduce carbon dioxide than carbon monoxide and if you manage to reduce carbon dioxide you can reduce the carbon monoxide as well.

This reaction it will take place in the presence of catalyst at a specific temperature and pressure.

CO₂ + 4 H₂ → CH₄ + 2 H₂O

Now taking into the account the chemical reaction we devise the following reasoning:

if 1 mole of CO₂ react with 4 moles of H₂

then 6.5 moles of CO₂ react with X moles of H₂

X = (6.5 × 4) / 1 = 26 moles of H₂

number of moles = mass / molecular wight

mass = number of moles × molecular wight

mass of H₂ = 26 × 2 = 52 g

Learn more about:

hydrogenation reaction

brainly.com/question/13592967

#learnwithBrainly

3 0

4 years ago