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nordsb [41]
3 years ago
10

Which of the following atoms is likely to transfer (and lose) an electron when it forms an ion? Please choose the correct answer

from the following choices, and then select the submit answer button. an atom containing 6 electrons an atom containing 2 electrons an atom containing 11 electrons an atom containing 10 electrons an atom containing 8 electrons
Chemistry
1 answer:
mestny [16]3 years ago
8 0

Answer:

An atom containing 11 electrons

Explanation:

Metal atoms form ions by a loss of electrons whereas non-metal atoms form ions by the gain of electrons.

The group 1 elements or alkali metals form lose their one valence shell electrons when forming ions; Group 2 metals lose two while Group 3 lose three. On the other hand, non-metal atoms found in Group 5, 6, and 7 forms ions by gaining one, two and three electrons respectively.

Using the electronic configuration of atoms, their groups in the Periodic Table can be determined.

An atom containing 6 electrons has the configuration 2,4 and thus belongs to Group 4.

An atom with 2 electrons belongs to Group 2

An atom with 11 electrons has the configuration 2,8,1 and thus belongs to Group 1

An atom with 10 electrons has the configuration 2,8 and thus belongs to Group 8

An atom with 8 electrons has the configuration 2,6 and thus belongs to Group 6.

From the above, it can be seen that an atom containing 11 electrons belongs to Group 1 and will lose an electron to form an ion.

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3. If you start with 8x1025 molecules of Cl, and 25 grams of KI, how many grams of KCl would
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Answer:

Percent yield = 89.1%

Explanation:

Based on the equation:

Cl₂ + 2KI → 2KCl + I₂

<em>1 mole of Cl₂ reacts with 2 moles of KI to produce to moles of KCl</em>

<em />

To solve this quesiton we must find the moles of each reactant in order to find the limiting reactant. With the limiting reactant we can find the moles of KCl and the mass:

<em>Moles Cl₂:</em>

8x10²⁵ molecules * (1mol / 6.022x10²³ molecules) = 133 moles

<em>Moles KI -Molar mass: 166.0028g/mol-</em>

25g * (1mol / 166.0028g) = 0.15 moles

Here, clarely, the KI is the limiting reactant

As 2 moles of KI produce 2 moles of KCl, the moles of KCl produced are 0.15 moles. The theoretical mass is:

0.15 moles * (74.5513g / mol) =

11.2g KCl

Percent yield is: Actual yield (10.0g) / Theoretical yield (11.2g) * 100

<h3>Percent yield = 89.1%</h3>
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