All categories

2 years ago

What is the frequency of a wave with a wavelength of 15 m and a wavespeed of 300 m/s?

Physics

1 answer:

STatiana [176]2 years ago

6 0

Answer: f=20 (i think)

Explanation:

all I did was divide 300 and 15.

300/15= 20

You might be interested in

What power rating of resistors would you use in the application required it to handle<br> 0.6W?

aliya0001 [1]

I would use a resistor rated for 1 W or more. Not less.

5 0

2 years ago

This group of elements is in group 2?

asambeis [7]

Answer:

If you meant the Periodic Table it's the alkaline-earth metal

beryllium (Be)

magnesium (Mg)

calcium (Ca)

strontium (Sr)

barium (Ba)

radium (Ra)

Explanation:

5 0

1 year ago

List out any 4 objectives of education

e-lub [12.9K]

- vocational aim
- cultural aim
- spiritual aim
- intellectual aim

6 0

2 years ago

A farmer lifts his hay bales into the top loft of his barn by walking his horse forward with a constant velocity of 1 ft/s. Dete

Lesechka [4]

Answer:

The velocity of the hay bale is - 0.5 ft/s and the acceleration is $6.25\times 10^{- 3} ft/s^{2}$

Solution:

As per the question:

Constant velocity of the horse in the horizontal, $v_{x} = 1 ft/s$

Distance of the horse on the horizontal axis, x = 10 ft

Vertical distance, y = 20 ft

Now,

Apply Pythagoras theorem to find the length:

$20^{2} + 10^{2} = l^{2}$

$l^{2}= 500$

Now,

$x^{2} + y^{2} = 500$ (1)

Differentiating equation (1) w.r.t 't':

$2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 0$

$x\frac{dx}{dt} = - y\frac{dy}{dt}$

where

$\frac{dx}{dt}$ = Rate of change of displacement along the horizontal

$\frac{dy}{dt}$ = Rate of change of displacement along the vertical

$v_{x}$ = velocity along the x-axis.

$v_{y}$ = velocity along the y-axis

$xv_{x} = -yv_{y}$

$v_{y} = - 10\times \frac{1}{20} = - 0.5 ft/s$

$|v_{y}| = 0.5\ ft/s$

Acceleration of the hay bale is given by the kinematic equation:

$v_{y}^{2} = u_{y} + 2ay$

$(-0.5)^{2} =0 + 2ay$

$0.25 = 2ay$

$\frac{0.25}{2y} = a$

$a = \frac{0.25}{2\times 20} = 6.25\times 10^{- 3} ft/s^{2}$

7 0

2 years ago

If your speedometer has an uncertainty of 2.5 km/h at a speed of 92 km/h, what is the percent uncertainty

Elis [28]

Answer:

2.7%

Explanation:

Given:

Uncertainty of the speedometer (u)= 2.5km/h

Speed measured at that uncertainty (v) = 92km/h

Percent uncertainty (p) is given as the ratio of the uncertainty to the speed measured then multiplied by 100%. i.e

p = $\frac{u}{v} * 100$ %

p = $\frac{2.5}{92} * 100$ %

p = 2.7%

Therefore, the percent uncertainty is 2.7%

6 0

2 years ago