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4 years ago

A solid metal can absorb heat from another object through which method of heat transfer?

Physics

2 answers:

Artist 52 [7]4 years ago

7 0

The answer is A).Conduction

lianna [129]4 years ago

3 0

Answer:

This method is called conduction.

Explanation:

Conduction is the mode of heat transfer in which heat is transferred from one part of the medium to the another from particle to particle in the direction of fall of temperature without actual movement of heated particles.

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Name something that magnets has done for you in your life

kati45 [8]

Helped me learn how to spell words, held pictures or papers up, collected metal items that were lost

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2 years ago

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In a football game a kicker attempts a field goal. The ball remains in contact with the kicker's foot for 0.0580 s, during which

Fantom [35]

Answer:

V₀ₓ = 10.94 m/s

V₀y = 18.87 m/s

Explanation:

To find the launch velocity, we use 1st equation of motion.

Vf = Vi + at

where,

Vf = Final Velocity of Ball = Launch Speed = V₀ = ?

Vi = Initial Velocity = 0 m/s (Since ball was initially at rest)

a = acceleration = 376 m/s²

t = time = 0.058 s

Therefore,

V₀ = 0 m/s + (376 m/s²)(0.058 s)

V₀ = 21.81 m/s

Now, for x-component:

V₀ₓ = V₀ Cos θ

where,

V₀ₓ = x-component of launch velocity = ?

θ = Angle with horizontal = 59.9⁰

V₀ₓ = (21.81 m/s)(Cos 59.9°)

V₀ₓ = 10.94 m/s

for y-component:

V₀ₓ = V₀ Sin θ

where,

V₀y = y-component of launch velocity = ?

θ = Angle with horizontal = 59.9⁰

V₀y = (21.81 m/s)(Sin 59.9°)

V₀y = 18.87 m/s

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4 years ago

5. Alex goes cruising on his dirt bike. He rides 700 m north, 300 m east, 400 m north, 600 m west, 1200 m south 300 m east and f

Gala2k [10]

Answer:

Explanation:

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3 years ago

A rod (length = 2.0 m) is uniformly charged and has a total charge of 5.0 nC. What is the electric potential (relative to zero a

Ksenya-84 [330]

Answer:

The electric potential is $V = 15.6 V$

Explanation:

From the question we are told that

The length of the rod is $L = 2.0 \ m$

The total charge of the rod is $q =5.0 nC = 5.0*10^{-9} C$

The length from the center is $d = 3.0 \ m$

The diagram illustrating the setup for this question is shown on the first uploaded image

From the diagram the potential at point A $dl$ is mathematically represented as

$dV = K \frac{dq}{l}$

Where K is the coulomb constant with a value $K = 9*10^9 \ Nm^2 /C^2$

where q is the charge in charge the rod relative to its distance from A is mathematically represented as

$dq = \frac{q}{L} dl$

This a small unit length of the rod

So $V = \frac{q}{L} \int\limits^4_2 {\frac{dl}{l} } \,$

=> $V = k\frac{q}{L} ln [\frac{4}{2} ]$

$V = k\frac{q}{L} ln2$

Substituting values

$V = 9* 10^9 * \frac{5*10^{-9}}{2} * ln 2$

$V = 15.6 V$

7 0

4 years ago

Based on your answer,what idea comes in to your mind?

valkas [14]

Answer:

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Explanation:

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3 years ago