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2 years ago

What is the solution to the equation 5x=6?

2 answers:

4 0

Answer: To find equation solutions, solve x+2=0 and x+3=0. To find equation solutions, solve x + 2 = 0 and x + 3 = 0. x2+5x+6=0 Two solutions were found : x = -2 x = -3 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2+5x+6 The first term is, x2 its ...

Step-by-step explanation:

Leni [432]2 years ago

3 0

Answer:

6 / 5 ( or ) 1.2

Step-by-step explanation:

5x = 6

x = 6 / 5

( or )

x = 1.2

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What is the product of 6x + 6 and 8x?

spin [16.1K]

Answer: 56

Step-by-step explanation: so you have 6 already and x is next to it and it says x=8 so put the eight where next to the six and since there is nothing in the middle than you multiple 6 8 idk the other number

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3 years ago

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A section of a rectangle is shaded to form a rhombus. The length of one side of the rectangle is 15, and the height is x.

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3 years ago

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The sum of the square root of a number and 6

Anna007 [38]

Answer:

Step-by-step explanation:

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3 years ago

Find all the zeroes of the equation(with simple steps).

uysha [10]

Answer-

The zeros are, $5,\ -5,\ 4i,\ -4i$

Solution-

$\Rightarrow -3x^4+27x^2+1200=0$

$\Rightarrow -3(x^2)^2+27(x^2)+1200=0$

Here,

a = -3, b = 27, c = 1200

So,

$x^2=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\dfrac{-27\pm \sqrt{-27^2-4\cdot (-3)\cdot 1200}}{2\cdot (-3)}$

$=\dfrac{-27\pm \sqrt{729+14400}}{-6}$

$=\dfrac{-27\pm 123}{-6}$

$=\dfrac{-27+123}{-6},\ \dfrac{-27- 123}{-6}$

$=\dfrac{96}{-6},\ \dfrac{-150}{-6}$

$=-16,\ 25$

So,

$\Rightarrow x^2=25,\ -16$

$\Rightarrow x=\sqrt{25},\ \sqrt{-16}$

$\Rightarrow x=5,\ -5,\ 4i,\ -4i$

8 0

3 years ago

Round 202.366 to the nearest hundredth

GuDViN [60]

Hello there,

202.366 to the nearest hundredth would be 202.37.

So what I did was I look at the 366 in the problem.

We want to round the to the nearest hundredth.

So what we would do it notice how the 66 in over 50.

The rule is if it's over 50, we round it to the nearest.

So your answer would be 202.37.

Hope this helps.

~Jurgen

3 0

3 years ago