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charle [14.2K]
3 years ago
14

sound waves generated in a classroom must _______ through an open doorway in order to propagate into the hallway. reflect refrac

t diffract
Physics
2 answers:
quester [9]3 years ago
5 0
<h3><u>Answer;</u></h3>

Diffract

Sound waves generated in a classroom must <em><u>diffract</u></em> through an open doorway in order to propagate into the hallway.

<h3><u>Explanation;</u></h3>
  • <em><u>Sound waves are a type of mechanical waves that requires a material medium for transmission,</u></em> they are longitudinal wave with all the properties of other waves.
  • <em><u>Diffraction is one of the property of waves that involves a change in direction of waves as they pass through an opening or around a barrier in their path. </u></em><u><em>Sound wave diffract around corners or through the door openings, allowing people to hear others speaking to us from rooms that are adjacent. </em></u>
galina1969 [7]3 years ago
3 0
<span>Sound waves generated in a classroom must diffract  through an open doorway in order to propagate into the hallway. </span>
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Metodo medible que no altera la composicion quimica de la materia o cuerpo?
SCORPION-xisa [38]

Answer:

Las propiedades físicas, como la dureza y el punto de ebullición, y los cambios físicos, como la fusión o la congelación, no implican un cambio en la composición de la materia.

Explanation:Creo que es correcta

3 0
3 years ago
Two blocks with masses 1 and 2 are connected by a massless string that passes over a massless pulley as shown. 1 has a mass of 2
Bess [88]

Answer:

The acceleration of M_2 is  a =  0.7156 m/s^2

Explanation:

From the question we are told that

    The mass of first block is  M_1 =  2.25 \ kg

    The angle of inclination of first block is  \theta _1 =  43.5^o

    The coefficient of kinetic friction of the first block is  \mu_1  = 0.205

      The mass of the second block is  M_2 = 5.45 \ kg

     The angle of inclination of the second block is  \theta _2 =  32.5^o

      The coefficient of kinetic friction of the second block is \mu _2 = 0.105

The acceleration of M_1 \ and\  M_2 are same

The force acting on the mass M_1 is mathematically represented as

     F_1 = T -  M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1

=> M_1 a = T -  M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1

Where T is the tension on the rope

The force acting on the mass M_2 is mathematically represented as    

  F_2 =  M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2

   M_2 a =  M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2

At equilibrium

  F_1 =  F_2

So

 T -  M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1 =M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2

making a the subject of the formula

    a =  \frac{M_2 g sin \theta_2 - M_1 g sin \theta_1 - \mu_1 M_1g cos \theta - \mu_2 M_2 g cos \theta_2 }{M_1 +M_2}

substituting values a =  \frac{(5.45) (9.8) sin (32.5) - (2.25) (9.8) sin (43.5) - (0.205)*(2.25) *9.8cos (43.5) - (0.105)*(5.45) *(9.8) cos(32.5) }{2.25 +5.45}

    => a =  0.7156 m/s^2

     

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4 years ago
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Answer:

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7 0
3 years ago
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A parallel RC circuit has a capacitive reactance of 962 ohms and a resistance of 1,200 ohms what is the impedance of this circui
Alex777 [14]

Answer:

<em>A. 751 ohm</em>

Explanation:

Impedance: <em>This is the total opposition to the flow of current in an a.c circuit by any or all of the three circuit elements ( R, L, C). The unit of impedance is Ohms (Ω). The impedance in a parallel circuit is gives a s</em>

<em>Z = RXₐ/√(Xₐ² + R²)............................... Equation 1</em>

<em>Where Z = The impedance of the a.c circuit, Xₐ = capacitive reactance, R = resistance.</em>

<em>Given: Xₐ = 962 Ω, R = 1200 Ω</em>

<em>Substituting these values into equation 1,</em>

<em>Z = 962×1200/√(962² + 1200²)</em>

<em>Z = 1154400/√(925444 + 1440000)</em>

<em>Z = 1154400/√(925444+1440000</em>

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<em>Z = 750.59 Ω</em>

<em>Z≈ 751 Ω</em>

<em>Therefore the impedance of the circuit = 751 Ω</em>

<em>The right option is A. 751 ohm</em>

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