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3 years ago

WHO IS GOOD AT PHYSICS, ELECTRIC CIRCUITS?

1 answer:

8 0

Answer: An electric circuit is a representation of how current moves from the source of the current( example a battery or a cell) through resistors and other devices before entering the source.

Explanation:

The two important types of electrical circuit includes:

--> open circuit and

--> closed circuit.

A circuit is said to be open when the electrical source, such as the battery or the cell, is not connected to any external conductor (or resistance). In this situation, any voltmeter connected across the terminal of the cell measures the total driving force of the cell.

In this type of circuit, current cannot flow from one end of power source to the other due to interruptions.

A circuit is said to be closed if the source of electricity is connected to an external conductor through which current is passed.

In a closed circuit, there is complete electrical connection which allows current to flow or circulate. Here, part of the total driving force of the source is used to drive current through the external resistance and the difference is used to overcome the internal resistance of the battery.

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A street light is at the top of a 19 foot tall pole. A woman 5.25 feet tall walks towards the pole with a speed of 7ft/sec along

bezimeni [28]

Answer:

The tip of her shadow is moving at the speed of 9.66 ft/sec

Explanation:

The height of the street light = 19 feet

The height of the woman = 5.25 feet

Distance between the woman and the base of the pole, x = 35 ft

The speed of the woman towards the pole, dx/dt = 7ft/sec

The distance from the base of the streetlight to the tip of the woman's shadow = y

The distance from the woman to the tip of her shadow = y - x

The diagram illustrating this description is shown below

Using similar triangle:

$\begin{gathered} \frac{19}{5.25}=\text{ }\frac{y}{y-x} \\ 19(y-x)\text{ = 5.25y} \\ 19y-19x\text{ = 5.25y} \\ 19y-5.25y\text{ = 19x} \\ 13.75y\text{ = 19x} \\ y\text{ = }\frac{19}{13.75}x \\ y\text{ = }1.38x \end{gathered}$

Find the derivative of both sides with respect to time, t

$\begin{gathered} \frac{dy}{dt}=\text{ 1.38}\frac{dx}{dt} \\ \frac{dy}{dt}=\text{ 1.38(7)} \\ \frac{dy}{dt}\text{ = }9.66\text{ ft/sec} \end{gathered}$

The tip of her shadow is moving at the speed of 9.66 ft/sec

7 0

1 year ago

PLEASE HELP ME THIS IS VERY IMPORTANT!!!!!!!!!!!!! 20 points and I will give brainlyest

Phoenix [80]

Answer: I believe it’s location D. Or whichever is the location of slow crystallization.

Explanation: Slow crystallization of magma forms granite. Hope this helps. :)

6 0

3 years ago

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As an aid in working this problem, consult concept simulation 5.2. car a uses tires for which the coefficient of static friction

4vir4ik [10]

The speed for a curve of a given radius is proportional to the square root of the coefficient of static friction. The allowed speed in the second curve is about
(20 m/s)√(0.7/1.1) ≈ 15.95 m/s

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3 years ago

Please help

eimsori [14]

Answer:

It's important that we understand how the climate is changing, so that we can prepare for the future. Studying the climate helps us predict how much rain the next winter might bring, or how far sea levels will rise due to warmer sea temperatures
As the cold front passes, winds become gusty. There is a sudden drop in temperature, and also heavy rain, sometimes with hail, thunder, and lightning.

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3 years ago

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George determines the mass of his evaporating dish to be 3.375 g. He adds a solid sample to the evaporating dish, and the mass o

zhannawk [14.2K]

Explanation:

The given data is as follows.

Mass of evaporating dish = 3.375 g

Total mass = Mass of solid sample + evaporating dish

That is, Mass of solid sample + evaporating dish = 26.719 g

Therefore, we will calculate the mass of solid sample as follows.

Mass of solid sample = (Mass of solid sample + evaporating dish) - mass of evaporating dish

= 26.719 g – 3.375 g

= 23.344 g

Thus, we can conclude that mass of his solid sample must be 23.344 g.

3 0

4 years ago

WHO IS GOOD AT PHYSICS, ELECTRIC CIRCUITS?​

WHO IS GOOD AT PHYSICS, ELECTRIC CIRCUITS?