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qaws [65]
3 years ago
12

If an object weighing 32lbs is acted upon by a net force of 32 lbs, what will be its acceleration?

Physics
2 answers:
Furkat [3]3 years ago
6 0
That"s exactly the situation when you drop the object off the roof or out of a tree... then the net force on it is the ONLY force on it, I.e. the force of gravity, and its acceleration is the acceleration due to gravity ... 32 ft/sec^2 .
ohaa [14]3 years ago
6 0

the acceleration would be 0 because lifting force up Is the same as the gravity going down. And therefore will not accelerate. The object has no net force
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the solubility product of lead fluoride is 3.6 x 10–8. what is its solubility in 0.10M NaF solution, in grams per liter
BartSMP [9]

Answer:

8.8 × 10⁻³ g/L

Explanation:

NaF is a strong electrolyte that ionizes according to the following reaction.

NaF(aq) → Na⁺(aq) + F⁻(aq)

Then, the concentration of F⁻ will also be 0.10 M.

In order to find the solubility of PbF₂ (S), we will use an ICE Chart.

        PbF₂(s) ⇄ Pb²⁺(aq) + 2 F⁻(aq)

I                           0                0.10

C                         +S               +2S

E                          S              0.10 + 2S

The solubility product (Kps) is:

Kps = 3.6 × 10⁻⁸ = [Pb²⁺].[F⁻]² = S . (0.10 + 2S)²

In the term 0.10 + 2S, 2S is negligible in comparison with 0.10 and we can omit it to simplify calculations.

Kps = 3.6 × 10⁻⁸ = S . (0.10)²

S = 3.6 × 10⁻⁵ M

The molar mass of PbF₂ is 245.20 g/mol. The solubility of PbF₂ in g/L is:

3.6 × 10⁻⁵ mol/L × 245.20 g/mol = 8.8 × 10⁻³ g/L

4 0
3 years ago
13) A mass attached to the free end of a spring executes simple harmonic motion according to the equation y = (0.50 m) sin (18π
Kitty [74]

Hi there!

The period is given by:

T = \frac{2\pi}{w}

T = Period (sec)

w = angular frequency (rad/sec)

According to the equation for SHM in terms of position:

y(t) = Asin(ωt + φ)

A = Amplitude (m)

ω = angular frequency (rad/sec)

t = time (sec)

φ = phase angle

In this instance, the angular frequency is given as 18π.

Plug this value into the equation for T:

T= \frac{2\pi}{18\pi} = \frac{1}{9} = \boxed{0.111 s}

4 0
3 years ago
A 77.0 kg firefighter climbs a flight of stairs 8.0 m high. how much work is required? 0 incorrect: your answer is incorrect. j
Alex73 [517]
<span>6160 joules

    to lift 1 newton 1 metre requires 1 joule
 there are 10 newtons in one kilo

    so 77(kg) x 8 (metres) x 10 (newtons/kilo) = 6160 joules</span>
5 0
3 years ago
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