Answer:
The percentage of the mechanical energy of the oscillator lost in each cycle is 6.72%
Explanation:
Mechanical energy (Potential energy, PE) of the oscillator is calculated as;
PE = ¹/₂KA²
During the first oscillation;
PE₁ = ¹/₂KA₁²
During the second oscillation;
A₂ = A₁ - 0.0342A₁ = 0.9658A₁
PE₂ = ¹/₂KA₂²
PE₂ = ¹/₂K (0.9658A₁)²
PE₂ = (0.9658²)¹/₂KA₁²
PE₂ = (0.9328)¹/₂KA₁²
PE₂ = 0.9328PE₁
Percentage of the mechanical energy of the oscillator lost in each cycle;
Therefore, the percentage of the mechanical energy of the oscillator lost in each cycle is 6.72%
Based on the calculations, the kinetic energy of the model rocket at this point is equal to: A. 7,200 Joules.
<u>Given the following data:</u>
Mass = 1 kg.
Height = 500 m.
Velocity = 120 m/s.
<h3>How to calculate kinetic energy?</h3>
Mathematically, kinetic energy can be calculated by using this formula:
K.E = 1/2 × mv²
<u>Where:</u>
- K.E is the kinetic energy.
Substituting the given parameters into the formula, we have;
K.E = 1/2 × 1 × (120)²
K.E = 1/2 × 1 × 14,400
K.E = 7,200 Joules.
Read more on kinetic energy here: brainly.com/question/25959744
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Answer:
Matter
Explanation:
Any type of material is a matter. It can be anything that occupies space and have mass. It is a composition of atoms which in term is made up of electrons, protons and neutrons. All particles in our universe is matter because everything has some mass and it occupies space.
Answer:
the correct answer is wavelength
30 volts
E= IxR
See ohms law calculator image below