1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
avanturin [10]
3 years ago
8

A block with mass of 0.5 kg is forced against a horizontal spring of negligible mass. compressing the spring a distance of 0.20m

. When released, the block moves on a horizontal tabletop for 1 meter before coming to rest. The spring constant is 100N/m. What is the coefficient of friction between the block and the tabletop??
Physics
2 answers:
Alik [6]3 years ago
7 0

Answer:

\mu = 0.408

Explanation:

Here we know that work done by all force must be equal to change in kinetic energy of the block

so here we will have

W_{friction} + W_{spring} = K_f - K_i

here we know that

W_{friction} = -\mu mg d

W_{spring} = \frac{1}{2}kx^2

also we know that initially and finally block is at rest

so we have

\frac{1}{2} kx^2 - \mu mg d = 0 - 0

\frac{1}{2}(100)(0.20^2) - \mu (0.5)(9.81)(1) = 0

\mu = 0.408

miv72 [106K]3 years ago
5 0
<span>Required"mu" is given by:

mu*0.5*9.8*1 = 0.5*100*0.20^2 or 
mu = 4/9.8 = 0.408 or 0.41

Therefore, </span><span> the coefficient of friction between the block and the tabletop is 0.408 or rounded off to 0.41.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

</span>
You might be interested in
6) If a mass of an object is decreased to half and acting force is reduced by quarter the acceleration of its motion
Zepler [3.9K]

Answer:

Decreases to half.

Explanation:

From the question given above, the following data were obtained:

Initial mass (m₁) = m

Initial force (F₁) = F

Initial acceleration (a₁) =?

Final mass (m₂) = ½m

Final force (F₂) = ¼F

Final acceleration (a₂) =?

Next, we shall determine a₁. This can be obtained as follow:

F₁ = m₁a₁

F = ma₁

Divide both side by m

a₁ = F / m

Next, we shall determine a₂.

F₂ = m₂a₂

¼F = ½ma₂

2F = 4ma₂

Divide both side by 4m

a₂ = 2F / 4m

a₂ = F / 2m

Finally, we shall determine the ratio of a₂ to a₁. This can be obtained as follow:

a₁ = F / m

a₂ = F / 2m

a₂ : a₁ = a₂ / a₁

a₂ / a₁ = F/2m ÷ F/m

a₂ / a₁ = F/2m × m/F

a₂ / a₁ = ½

Cross multiply

a₂ = ½a₁

From the illustrations made above, the acceleration of the car will decrease to half the original acceleration

7 0
3 years ago
If you begin with 40 grams of a radioactive isotope and end with 10 grams, how many half-lifes of the radioactive isotope have p
Rom4ik [11]
30 grams of radioactive isotope have passed.
8 0
3 years ago
A doctor observe areas of pink scaly skin on patient
murzikaleks [220]

Answer:

0-0 what is rhat supposed to mean. i dont think anyone can answer that lol

6 0
2 years ago
Dana is on a train traveling at a speed of 20 km/h. Dana walks from the front of the train to the back of the train at a speed o
dezoksy [38]

Answer:

Diana's speed relative to ground is <u>16 km/h</u> in the direction of motion of train.

Explanation:

Given:

Velocity of train in forward direction is, v_{t,g}=20\ km/h

Here, v_{t,g}\to \textrm{velocity of the train relative to ground.}

Velocity of Diana relative to train in the backward direction is, v_{D,t}=-4\ km/h

Negative sign implies backward motion or motion opposite to the direction of train's motion. Here, Diana is walking from front of train to back. So, Diana is moving in the opposite direction.

Now, we know that, for two bodies 'A' and 'B', velocity of 'A' relative to ground is given as:

v_{A,g}=v_{B,g}+v_{A,B}

Therefore, velocity of Diana relative to ground is given as:

v_{D,g}=v_{t,g}+v_{D,t}

v_{D,g}=(20-4)\ km/h

v_{D,g}=16\ km/h

So, Diana's speed relative to ground is 16 km/h in the direction of motion of train.

5 0
3 years ago
Appropriate word inside the parentheses.
Taya2010 [7]

Answer:

<em>At constant mass, the  acceleration of an object varies (</em><em>directly</em><em>) with the net external force  applied. That is to say, that an object's acceleration increases as the force applied is (</em><em>increased</em><em>),  but its acceleration decreases if the force applied is (</em><em>decreased</em><em>).</em>

Explanation:

<u>Mechanical Force </u>

According to the second Newton's law, the acceleration of an object varies directly proportional to the external net force applied and inversely proportional to the mass of the object.

If the mass is constant, then the acceleration will vary in the same way as the force does.

Completing the sentences:

At constant mass, the  acceleration of an object varies (directly) with the net external force  applied. That is to say, that an object's acceleration increases as the force applied is (increased),  but its acceleration decreases if the force applied is (decreased).

6 0
3 years ago
Other questions:
  • Which statement best describes the scientists who contributed to our current body of scientific knowledge
    12·1 answer
  • What does the nervous system allow?
    12·1 answer
  • Suppose we wish to use a 8.0 m iron bar to lift a heavy object by using it as a lever. If we place the pivot point at a distance
    13·1 answer
  • A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that incre
    13·1 answer
  • Which equation shows the relationship of wave speed to
    15·1 answer
  • Find analytically the velocity of the object at the end point of the inclined plane for a certain angle Ө
    8·1 answer
  • Michelle walked 217 meters in 2 minutes ,55 seconds what is her speed
    9·1 answer
  • Andrew is riding his bike is riding in a circle that has a radius of 10 m. He keeps
    5·1 answer
  • An astronomical unit (A.U.) is 1 point A) a term for defining the luminosity of a star B) the average distance from the Earth to
    6·1 answer
  • Advantages of using tidal power include _____. no air pollution tides are predictable low environmental impact all of these
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!