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Arada [10]
3 years ago
8

When a car is weighed, it is driven slowly on a horizontal floor over a scale that records a reading as the front wheels go over

the scale, and then records a second reading as the rear wheels go over the scale. The weight of the car is equal to
A) the weight under the rear wheels.

B) the average of the two weights.

C) the sum of the two weights.

D) the weight under the front wheels.

E) the difference of the two weights.
Physics
1 answer:
Ymorist [56]3 years ago
7 0

Answer: C

Explanation:

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The impact front the fall, depending on the distance, has an effect on the impact of their bones crushing with the pressure from the fall.
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Which variable is represented by the following symbol? ∑F
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d.Net force

Explanation:

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The average 8- to 18-year-old spends __________ per day on average in front of a screen doing very little to no physical activit
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D. 3 hours or more

Explanation:

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2 years ago
Charge A and charge B are 2.2 m apart. Charge A is 1.0 C, and charge B is
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6 0
3 years ago
Your starship, the Aimless Wanderer,lands on the mysterious planet Mongo. As chief scientist-engineer,you make the following mea
Setler [38]

Answer:

a)  M = 4,997 10²⁰ kg ,  b)   T = 1.43 10³ s

Explanation:

a) This exercise should be solved in several parts, let's start by calculating the acceleration of gravity of this planet from kinematics

          v = v₀ - a t

As it indicates that there is no atmosphere, the friction force is zero and the initial and final velocity have the same module, but the opposite direction

         a = (v₀ - v) / t

         a = (15 - (-15)) /9.00 = 30/9

         a = 3.33 m / s²

Now we use Newton's second law where force is the force of universal attraction

          F = m a

         G m M / r² = m a

         M = a r² / G

Let's calculate

         M = 3.33 (1.00 10⁵)² / 6.67 10⁻¹¹

         M = 4,997 10²⁰ kg

b) The period of the ship's orbit

In this case we have a centripetal acceleration

The radius of the orbit is the radius of the plant plus the height of the ship from the surface

         R = R_{m} + h

         R = 1 10⁵ + 2.00 10⁴

         R = 12 10⁴ m

         F = m a

        G m M / R² = m a

Centripetal acceleration is

         a = v² / R

The orbit is circular therefore the velocity module is constant, so we can use the equation of uniform motion, where the distance is the length of the orbit, for a circle

        d = 2π R

        v = d / t

        v = 2π R / T

Let's replace

        G m M / R² = m (2π R / T)² / R

        G M = R³ 4π² / T²

        T² = 4π² R³ / G M

       T² = (4π² (12 10⁴)³ / (6.67 10⁻¹¹ 4,997 10²⁰)

       T² = 6.82 10¹⁶ / 3.33 10¹⁰

       T = √ (2,048 10⁶)

       T = 1.43 10³ s

3 0
3 years ago
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