Answer:
646.6 nm
Explanation:
Using the data given, we fit a linear model :
Spectroscope Readings Known Helium Wavelengths (nm)
3.65 388.9
4.75 486.6
4.90 501.6
5.65 587.6
6.45 667.8
7.00 706.5
Using technology like excel to fit the model, the regression model obtained is :
Y = 97.96582X + 27.48458
Where, y is the predicted or corrected wavelength value.
This mod could be used to calculate the corrected wavelength for a given Spectroscope value :
Given a Spectroscope value of 6.32 ; the corrected wavelength is obtained by replacing x in the equation by 6.32 and calculate y ;
Y = 97.96582X + 27.48458
x = 6.32
Y = 97.96582(6.32) + 27.48458
Y = 619.1439824 + 27.48458
Y = 646.6285624
Corrected wavelength value is : 646.6
Answer:
Explanation:
Given
diameter ![d=80\ m](https://tex.z-dn.net/?f=d%3D80%5C%20m)
runner start at (x,y)=(48 m,0 m)
Runner runs around the circle 2.5 times
i.e. he runs two and half rounds
displacement of two rounds is zero so net displacement is of half round
displacement ![=\pi \cdot 48=150.816\ m](https://tex.z-dn.net/?f=%3D%5Cpi%20%5Ccdot%2048%3D150.816%5C%20m)
After 2.5 round he will be towards west direction with respect to origin
so direction of displacement vector is west
Answer:
The answer is 1200 Kg
Explanation:
<h3><u>Given</u>;</h3>
<h3>
<u>To </u><u>Find</u>;</h3>
<h3><u>Formula</u>;</h3>
- W = m × g
- where, W = weight
- m = mass,
- g = Acceleration due to gravity = 10 m/s²
Now,
W = mg
12000 = m ÷ 10
m = 12000 ÷ 10
m = 1200 kg
Thus, The mass of car is 1200 kg or 1.2k Kg.
<u>-TheUnknownScientist 72</u>
The answer is c capacitance
Answer:
100 A.
Explanation:
From the question given above, the following data were obtained:
Electrochemical equivalent (Z) = 0.0012 g/C
Mass (M) = 36 g
Time (t) = 5 mins
Current (I) =?
Next, we shall determine the charge. This can be obtained as follow:
Electrochemical equivalence (Z) = 0.0012 g/C
Mass (M) = 36 g
Charge (Q) =.?
M = ZQ
36 = 0.0012 × Q
Divide both side by 0.0012
Q = 36 / 0.0012
Q = 30000 C
Next, we shall convert 5 mins to s. This can be obtained as follow:
1 min = 60 s
Therefore,
5 mins = 5 × 60
5 mins = 300 s
Finally, we shall determine the current. This can be obtained as shown below:
Charge (Q) = 30000 C
Time (t) = 300 s
Current (I) =?
Q = It
30000 = I × 300
Divide both side by 300
I = 30000 / 300
I = 100 A
Therefore, the current is 100 A.