Question

Which temperature is the hottest? 98 F or 39 C or 303K? F= 1.8C + 32 C= (F-32)/1.8

Answer 1

Answer:

The hottest temperature is  $T_2 = 39^o C$

Explanation:

From the question we are given

    $T_1 = 98 F$

  $T_2 = 39^oC$

  $T_3 = 303 \ K$

Generally converting $T_3$ to  Fahrenheit

    $T_3' = (T_3 -273 ) * \frac{9}{5} + 32$

=> $T_3' = (303 -273 ) * \frac{9}{5} + 32$

=> $T_3' = 86 F$

Converting  $T_2$ to  Fahrenheit

      $T_2' = T_2 * \frac{9}{5} + 32$

=> $T_2' = 39 * \frac{9}{5} + 32$

=> $T_2' =102.2 F$  

Now comparing  the temperature  in Fahrenheit we see that $T_2$  is the hottest