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puteri [66]
3 years ago
7

Which temperature is the hottest? 98 F or 39 C or 303K? F= 1.8C + 32 C= (F-32)/1.8

Physics
1 answer:
sergejj [24]3 years ago
3 0

Answer:

The hottest temperature is  T_2 = 39^o C

Explanation:

From the question we are given

    T_1 =  98 F

  T_2 =  39^oC

  T_3 =  303 \  K

Generally converting T_3 to  Fahrenheit

    T_3' =  (T_3 -273 ) * \frac{9}{5}  + 32

=> T_3' =  (303 -273 ) * \frac{9}{5}  + 32

=> T_3' = 86 F

Converting  T_2 to  Fahrenheit

      T_2' =  T_2 * \frac{9}{5}  + 32

=> T_2' =  39 * \frac{9}{5}  + 32

=> T_2' =102.2 F  

Now comparing  the temperature  in Fahrenheit we see that T_2  is the hottest

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Answer:

Distance = velocity x time, so 10 m/s X 10 s = 100 m

Explanation:

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Your average velocity will be half of your final, because you accelerated at a constant rate. So your average velocity is 10 m/s.

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Answer:

0.75 grams

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