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3 years ago

Which temperature is the hottest? 98 F or 39 C or 303K? F= 1.8C + 32 C= (F-32)/1.8

Physics

1 answer:

sergejj [24]3 years ago

3 0

Answer:

The hottest temperature is $T_2 = 39^o C$

Explanation:

From the question we are given

$T_1 = 98 F$

$T_2 = 39^oC$

$T_3 = 303 \ K$

Generally converting $T_3$ to Fahrenheit

$T_3' = (T_3 -273 ) * \frac{9}{5} + 32$

=> $T_3' = (303 -273 ) * \frac{9}{5} + 32$

=> $T_3' = 86 F$

Converting $T_2$ to Fahrenheit

$T_2' = T_2 * \frac{9}{5} + 32$

=> $T_2' = 39 * \frac{9}{5} + 32$

=> $T_2' =102.2 F$

Now comparing the temperature in Fahrenheit we see that $T_2$ is the hottest

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2 years ago

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Answer:

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Explanation:

from the question we are told that

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$TM = \frac{1}{2} * k * A^2$

Here k is the spring constant , A is the total displacement of the the mass from maximum compression to maximum extension of the spring

Generally this total mechanical energy is mathematically represented as

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Here the potential energy of the mass is mathematically represented as

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Here x is the displacement of the mass from maximum compression or extension of the spring to equilibrium position and the value is

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$PE = \frac{1}{ 2} * k * [ \frac{A}{2} ]^2$

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So the ratio of $KE : TM$ is mathematically represented as

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