Just need help with this question
1 answer:
we know the diameter of the circle is 54, so the radius of it is half that or 27.
![\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=27 \end{cases}\implies A=\pi (27)^2\implies \stackrel{using~\pi =3.14}{A=2289.06~mi^2}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D27%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2827%29%5E2%5Cimplies%20%5Cstackrel%7Busing~%5Cpi%20%3D3.14%7D%7BA%3D2289.06~mi%5E2%7D)
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It would be $13.52 for 11 cans of soup
Answer:
7 Groups of 1/2 in 3 1/2
Answer:
4
Step-by-step explanation:
3- 3
23 - 3
20 / 5 = 4.
4 x 5 + 3 = 23, so X is 4.
