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trasher [3.6K]
2 years ago
7

A scale measures the weight of a light object to be 11.000 lbs ± 0.034 lbs. what is the uncertainty if this same scale is use to

measure an object that weights 78.000 lbs? Assume that the percent uncertainty of the scale remains constant
1)0.034lbs
2)0.044lbs
3)0.310lbs
4)0.240Ibls
Physics
1 answer:
Gre4nikov [31]2 years ago
6 0

The uncertainty of the heavy object if the scale remains constant is 0.24 lbs.

<h3>What is uncertainty in measurement?</h3>
  • This is the error associated in an attempt measure the object accurately.

The percent uncertainty in measuring the light weight object is calculated as follows;

= \frac{0.034}{11} \times 100\%\\\\= 0.309\%

The uncertainty of the heavy object if the scale remains constant is calculated as follows;

= \frac{0.309}{100} \times 78.0 \ lbs\\\\= 0.24 \ lbs

Learn more about percent uncertainty here: brainly.com/question/5493941

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Explanation:

Centripetal acceleration is:

a = v² / r

a = (4.0 m/s)² / 0.60 m

a = 26.6 m/s²

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lisabon 2012 [21]

Answer:

<h2>1116.9 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

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From the question we have

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We have the final answer as

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3 years ago
If the area of an iron rod is 10 cm by 0.5 cm and length is 35 cm. Find the value of resistance, if 11x10^-8 ohm.m be the resist
malfutka [58]

Answer:

Resistance of the iron rod, R = 0.000077 ohms    

Explanation:

It is given that,

Area of iron rod, A=10\ cm\times 0.5\ cm=5\ cm^2 = 0.0005\ m^2

Length of the rod, L = 35 cm = 0.35 m

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We need to find the resistance of the iron rod. It is given by :

R=\rho\dfrac{L}{A}

R=11\times 10^{-8}\times \dfrac{0.35\ m}{0.0005\ m^2}

R=0.000077 \Omega

So, the resistance of the rod is 0.000077 ohms. Hence, this is the required solution.

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Given

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0.263*10^-3 = b * 4.2427

b = 0.263*10^-3 / 4.2427

b = 0.0000620 T

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