I believe it would be 3 amps.
Answer:
Explanation:
velocity of first projectile after 3 s
v = u - gt
v = 49.4 - 9.8 x 3
= 20 m /s
Velocity of second projectile after 3 s after being dropped from rest
v = u + gt
= 0 + 9.8 x 3
= 29.4 m /s
They will be moving in opposite direction at the time of meeting , so their relative velocity
= 20 + 29.4 = 49.4 m /s
From the frame of reference of the first projectile, the velocity of the second projectile will be 49.4 m /s .
<span>René Descartes suggests this.</span>
Answer:
9.72s
Explanation:

Here we need to find out the time that the car took to achieve the velocity of 70km/hr after starting from rest . Firstly convert the final velocity in m/s by multiplying it by 5/18 , as ,
- As we know that the rate of change of velocity is known as acceleration , so ;
Plug in the respective values ,
Simplify ,
Cross multiply ,
Simplify
<h3>Hence the required answer is 9.72s.</h3>