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Ivan
3 years ago
6

You are heading toward an island in your speed boat when you see a friend standing on the shore of the island. You sound the boa

t's horn. Is the wavelength of the sound your friend perceives greater than, less than, or equal to the wavelength that would be heard without any motion of the boat, and why?
Physics
1 answer:
monitta3 years ago
8 0

Answer:

Greater than

Explanation:

The Wavelength will be higher than what will be heard without any motion on the boat due to the Doppler Effect, which is the change in the frequency of a sound wave whenever there's a relative motion between the source of the wave and observer. The amount of shift in frequency depends on the speed of the source towards the observer; the higher the velocity of the source, the higher the shift.

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What type of charge does an electron have?
GarryVolchara [31]

An electron has a negative charge. Hope this helps.

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3 years ago
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A school bus moves at speed of 35 mi/hr for 20 miles. How long will it take the bus to get to school
ludmilkaskok [199]

Answer:

Explanation:

Assuming school is at the end of the 20 mile route, then

20 mi / 35 mi/hr = 0.57142...hr

which is about 34 minutes 17 seconds

6 0
2 years ago
A small but measurable current of 3.8 × 10-10 A exists in a copper wire whose diameter is 2.5 mm. The number of charge carriers
Karolina [17]

Answer:

a) 4.9*10^-6

b) 5.71*10^-15

Explanation:

Given

current, I = 3.8*10^-10A

Diameter, D = 2.5mm

n = 8.49*10^28

The equation for current density and speed drift is

J = I/A = (ne) Vd

A = πD²/4

A = π*0.0025²/4

A = π*6.25*10^-6/4

A = 4.9*10^-6

Now,

J = I/A

J = 3.8*10^-10/4.9*10^-6

J = 7.76*10^-5

Electron drift speed is

J = (ne) Vd

Vd = J/(ne)

Vd = 7.76*10^-5/(8.49*10^28)*(1.60*10^-19)

Vd = 7.76*10^-5/1.3584*10^10

Vd = 5.71*10^-15

Therefore, the current density and speed drift are 4.9*10^-6

And 5.71*10^-15 respectively

3 0
3 years ago
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sammy [17]

Answer:

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Explanation:

5 0
2 years ago
6. If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would
Bezzdna [24]

Answer:

  175 m

Explanation:

The average velocity for constant acceleration is the average of the beginning and ending velocities. That is (0+39)/2=19.5 m/s. If the bicyclist rides for 9 seconds, the distance traveled is ...

  (9 s)(19.5 m/s) = 175.5 m

She would travel 175.5 meters in that time.

7 0
3 years ago
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