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alexgriva [62]
3 years ago
9

A 500g cart moving at 0.25 m/s collides and sticks to a stationary 750g cart. How fast do the two carts

Physics
1 answer:
Tresset [83]3 years ago
3 0

Answer:

0.1 m/s

Explanation:

Please see attached photo for explanation.

Mass of 1st cart (m₁) = 500 g

Initial velocity of 1st cart (u₁) = 0.25 m/s

Mass of 2nd cart (m₂) = 750 g

Initial velocity of 2nd cart (u₂) = 0 m/s

Velocity (v) after collision =.?

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(500 × 0.25) + (750 × 0) = v(500 + 750)

125 + 0 = v(1250)

125 = 1250v

Divide both side by 1250

v = 125 / 1250

v = 0.1 m/s

Thus, the two cart will move with a velocity of 0.1 m/s after collision.

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Explanation:

Draw a free body diagram for each disc.

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Wa = 86.5 N − T₁

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T₁ − T₂ − Wb = 0

Wb = T₁ − T₂

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∑F = ma

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The force of gravity is F_{g} =G \cdot \dfrac{M \cdot m}{r^{2}}

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The correct option for the question, acceleration of a free-falling object in a frictionless environment increases as a function of time is <u>False</u>

<u></u>

Learn more about object in free fall here:

brainly.com/question/13712424

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Hope this helps !

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