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alexgriva [62]
3 years ago
9

A 500g cart moving at 0.25 m/s collides and sticks to a stationary 750g cart. How fast do the two carts

Physics
1 answer:
Tresset [83]3 years ago
3 0

Answer:

0.1 m/s

Explanation:

Please see attached photo for explanation.

Mass of 1st cart (m₁) = 500 g

Initial velocity of 1st cart (u₁) = 0.25 m/s

Mass of 2nd cart (m₂) = 750 g

Initial velocity of 2nd cart (u₂) = 0 m/s

Velocity (v) after collision =.?

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(500 × 0.25) + (750 × 0) = v(500 + 750)

125 + 0 = v(1250)

125 = 1250v

Divide both side by 1250

v = 125 / 1250

v = 0.1 m/s

Thus, the two cart will move with a velocity of 0.1 m/s after collision.

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Answer:

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Explanation:

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If F stays the same and m decreases, then a increases.

Therefore, the magnitude of the train's acceleration increases (the acceleration becomes more negative).

6 0
3 years ago
What feature of the ocean basin is formed when old oceanic crust is forced under continental plates?
Sholpan [36]

Answer:

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Explanation:

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Ocean basin contain continental shelf,mid ocean ridge that is found on the sea floor.

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4 0
4 years ago
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4 0
4 years ago
Sodium has an atomic mass of 23 and an atomic number of 11, so the
horrorfan [7]

Answer:

12 Neutrons

Explanation:

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5 0
3 years ago
Now imagine a person dragging a 50 kg box along the ground with a rope, as
ANTONII [103]

Answer:

The coefficient of static friction between the box and floor is, μ = 0.061

Explanation:

Given data,

The mass of the box, m = 50 kg

The force exerted by the person, F = 50 N

The time period of motion, t = 10 s

The frictional force acting on the box, f = 30 N

The normal force on the box, η = mg

                                                     = 50 x 9.8

                                                     = 490 N

The coefficient of friction,

                            μ = f/ η

                               = 30 / 490

                               = 0.061

Hence, the coefficient of static friction between the box and floor is, μ = 0.061

7 0
4 years ago
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