Answer:
Explanation:
1) Resolution and uncertainty of both ADC ranges
a) Resolution (for +/- 5 mV range) = 5 mV / 2n where n = number of bits of ADC
Resolution = 5 mV / 28 = 5 mV / 256 = 0.0195 mV ..................1
uncertainty (for +/- 5 mV range) = +/- 0.5*resolution = +/- 0.5*0.0195 mV = 0.00975 mV ..........2
b) Resolution (for +/- 5 V range) = 5 V / 2n where n = number of bits of ADC
Resolution = 5 mV / 28 = 5 V / 256 = 0.0195 V = 19.5 mV ..................3
uncertainty (for +/- 5 mV range) = +/- 0.5*resolution = +/- 0.5*19.5 mV = 9.75 mV ..........4
2)Thermocouple sensitivity = ( Maximum output voltage - Minimum Output voltage) / (Maximum Temperature - Minimum Temperature)
Thermocouple sensitivity = (3.649mv - 0 ) / (70 - 0) = 0.0521 mV / Deg.C ............5
This is the required Thermocouple sensitivity
3) Water bath temperature is given as 57 deg.C
Hence voltage read by Thermocouple = Sensitivity*57 = 0.0521*57 mV = 2.9697 mV ........6
4)We need to use ADC with a range of +/- 5 mV range as ADC with +/- 5 V range can not do measurement as it's resolution is higher than output voltage.
ADC will measure voltage as 2.9695 mV ......................7
Answer:
1. Graph C
2. Friction
Explanation:
1. The line on all of the graphs shown represents velocity. The formula for velocity is
where d is distance and t is time. Focusing on the first lap, the starting point on the graph should be the origin and the "ending" point should be (20, 3). These requirements eliminate graph A as an answer because its "end" is not (20, 3). During the break, the student does not move, so the slope of the line should be completely horizontal. The break lasted for 5 minutes, so the correct graph should have a horizontal line between the points (20, 3) and (25, 3). This requirement eliminates graph B and D because their break is either not long enough (B) or too long (D).
2. Friction slows down the movement of objects. When an object is rough, it produces more friction which causes the object to be slowed more. When an object is smooth, friction slows it less than it would for a rough object.
I’m just here for points because I have test and I need them lol
The exit temperature is 586.18K and compressor input power is 14973.53kW
Data;
- Mass = 50kg/s
- T = 288.2K
- P1 = 1atm
- P2 = 12 atm
<h3>Exit Temperature </h3>
The exit temperature of the gas can be calculated isentropically as

Let's substitute the values into the formula

The exit temperature is 586.18K
<h3>The Compressor input power</h3>
The compressor input power is calculated as

The compressor input power is 14973.53kW
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