(5 points) Which of the following circuits may not be used to determine the value of the resistor? Circle all that apply.

Engineering

1 answer:

olga55 [171]2 years ago

8 0

The circuit that may not be used to determine the value of the resistor is (Option A). See the attached image.

<h3>What is a resistor?</h3>

A resistor is a component of an electronic circuit that restricts or regulates the passage of electrical current.

Resistors can also be used to supply a fixed voltage to an active device such as a transistor.

<h3>What is the purpose of a resistor?</h3>

A resistor is a two-terminal electrical component that offers resistance to current flow. Resistors are commonly employed in electrical circuits to reduce current flow, split voltages, impede transmission signals, and bias active parts.

<h3>What is a circuit?</h3>

Individual electronic components such as resistors, transistors, capacitors, inductors, and diodes are linked by electrical wires or traces through which electric current can pass to form an electronic circuit.

Learn more about circuits:

brainly.com/question/28039167
#SPJ1

You might be interested in

Blank is common during exercise.

dsp73

Answer:

Sweat

Explanation:

As you exercise you respire and warm up due to energy. In turn, two things happen, blood vessels vasodilate (irrelevant to you) and sweat glands sweat more. this sweat then evaporates and cools down the body.

7 0

2 years ago

(a) Consider a message signal containing frequency components at 100, 200, and 400 Hz. This signal is applied to a SSB modulator

MakcuM [25]

Answer:

Explanation:

The frequency components in the message signal are

f1 = 100Hz, f2 = 200Hz and f3 = 400Hz

When amplitude modulated with a carrier signal of frequency fc = 100kHz

Generates the following frequency components

Lower side band

$100k - 100 = 99.9kHz\\\\100k - 200 = 99.8kHz\\\\100k - 400 = 99.6kHz\\\\$

Carrier frequency 100kHz

Upper side band

$100k + 100 = 100.1kHz\\\\100k + 200 = 100.2kHz\\\\100k + 400 = 100.4kHz$

After passing through the SSB filter that filters the lower side band, the transmitted frequency component will be

$100k, 100.1k, 100.2k\ \texttt {and}\ 100.4kHz$

At the receive these are mixed (superheterodyned) with local ocillator frequency whichh is 100.02KHz, the output frequencies will be

$100.02 - 100.1k = 0.08k = 80Hz\\\\100.02 - 100.2k = 0.18k = 180Hz\\\\100.02 - 100.4 = 0.38k = 380Hz$

After passing through the SSB filter that filters the higher side band, the transmitted frequency component will be

$100k, 99.9k, 99.8k\ \ and \ \99.6kHz$

At the receive these are mixed (superheterodyned) with local oscillator frequency which is 100.02KHz, and then fed to the detector whose output frequencies will be

$100.02 - 99.9k = 0.12k = 120Hz\\\\100.02 - 99.8k = 0.22k = 220Hz\\\\100.02 - 99.6k = 0.42k = 420Hz$