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Ainat [17]
2 years ago
7

Alkaline batteries adopted their name from the _____ that is present in the reactions at both the zinc anode and the MnO2 cathod

e.
Chemistry
1 answer:
Paul [167]2 years ago
4 0

Answer:

hydroxide ion

Explanation:

The alkaline battery got this name because it has an alkaline electrolyte of potassium hydroxide.

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6 0
2 years ago
Why is this temperature scale (Celsius) different and/or better than the other temperature scales?
Vesna [10]

Answer:

They are used because of preference or convenience, not necessity. These scales came about historically when there were no standards to calibrate a thermometer against. The Fahrenheit scale used the temperature of the coldest thing then known for its zero, which was salty ice.13-Oct-2019

8 0
2 years ago
The sum of the oxidation numbers of all atoms in a neutral compound is
Phoenix [80]
The sum of the oxidation numbers of all atoms in a neutral compound is zero.
5 0
3 years ago
Read 2 more answers
What mass of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution?
inna [77]

Answer:

459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution

Explanation:

Molarity is a measure of the concentration of a solute in a solution that indicates the amount of moles of solute that appear dissolved in one liter of the mixture. In other words, molarity is the number of moles of solute that are dissolved in a given volume.

The Molarity of a solution is determined by the following expression:

Molarity=\frac{number of moles of solute}{volume}

Molarity is expressed in units \frac{moles}{liter}

In this case:

  • Molarity: 1.56 M= 1.56 \frac{moles}{liter}
  • Number of moles of calcium chlorine= ?
  • Volume= 2.657 liters

Replacing:

1.56 M=\frac{Number of moles of calcium chlorine}{2.657 liters}

Solving:

Number of moles of calcium chlorine= 1.56 M* 2.657 liters

Number of moles of calcium chlorine= 4.14 moles

In other side, you know:

  • Ca: 40 g/mole
  • Cl: 35.45 g/mole

Then the molar mass of the calcium chloride CaCl₂ is:

CaCl₂= 40 g/mole + 2* 35.45 g/mole= 110.9 g/mole

Now it is possible to apply the following rule of three: if in 1 mole there is 110.9 g of CaCl₂, in 4.14 moles of the compound how much mass is there?

mass=\frac{4.14 moles*110.9g}{1 mole}

mass= 459.126 g

<u><em>459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution</em></u>

3 0
2 years ago
Calculate the number of molecules in a deep breath of air whose volume is 2.15 L at body temperature, 37 ∘C, and a pressure of 7
Zinaida [17]
PV = nRT 
R = 0.0821 L * atm / mol * K 
(ideal gas constant) 

First, convert 735 torr to atm. Divide by 760. 
(1 atm = 760 torr) 

735 torr * 1 atm / 760 torr = 0.967 atm 
Then, convert 37 C to Kelvin. Just add 273. 
37 C = 310K 

n = PV / RT 
= (0.967)(2.07) / (0.0821)(310) 
= 0.0786 mol 

<span>0.0786 mol * 6.02 * 10^23 molecules / 1 mol = 4.73 * 10^22 molecules </span>
7 0
2 years ago
Read 2 more answers
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