The composite material is composed of carbon fiber and epoxy resins. Now, density is an intensive unit. So, to approach this problem, let's assume there is 1 gram of composite material. Thus, mass carbon + mass epoxy = 1 g.
Volume of composite material = 1 g / 1.615 g/cm³ = 0.619 cm³
Volume of carbon fibers = x g / 1.74 g/cm³
Volume of epoxy resin = (1 - x) g / 1.21 g/cm³
a.) V of composite = V of carbon fibers + V of epoxy resin
0.619 = x/1.74 + (1-x)/1.21
Solve for x,
x = 0.824 g carbon fibers
1-x = 0.176 g epoxy resins
Vol % of carbon fibers = [(0.824/1.74) ÷ 0.619]*100 =<em> 76.5%</em>
b.) Weight % of epoxy = 0.176 g epoxy/1 g composite * 100 = <em>17.6%</em>
Weight % of carbon fibers = 0.824 g carbon/1 g composite * 100 = <em>82.4%</em>
Answer:
1)KNO3 ( pottasium trioxonitrate (V)
2)Ca(NO3)2 (calcium trioxonitrate (V
Explanation:
1)KNO3 ( pottasium trioxonitrate (V)
2)Ca(NO3)2 (calcium trioxonitrate (V)
Thses two compounds are metallic compounds and does not react with either the acid or the base.
Write the type of metal, based on your examination of the periodic table?
1)KNO3 ( pottasium trioxonitrate (V) have a potassium element which belongs to group 2 of the Periodic table which is an alkaline metal and can react with water or steàm
2)Ca(NO3)2 (calcium trioxonitrate (V) has calcium metal element which is an alkaline earth metal in the Periodic table and they react with Hallogens
Answer:
Density = 8.75ml
Explanation:
Density = Mass / Volume
In this problem ...
Mass = 28 grams
Volume = 31.4ml - 28.2ml = 32ml (water displacement also)
∴Density = mass /volume = 28g/32ml = 8.75g/ml
The pressure exerted by 0.400 moles of carbon dioxide in a 5.00 Liter container at 25 °C would be 1.9563 atm or 1486.788 mm Hg.
<h3>The ideal gas law</h3>
According to the ideal gas law, the product of the pressure and volume of a gas is a constant.
This can be mathematically expressed as:
pv = nRT
Where:
p = pressure of the gas
v = volume
n = number of moles
R = Rydberg constant (0.08206 L•atm•mol-1K)
T = temperature.
In this case:
p is what we are looking for.
v = 5.00 L
n = 0.400 moles
T = 25 + 273
= 298 K
Now, let's make p the subject of the formula of the equation.
p = nRT/v
= 0.400 x 0.08206 x 298/5
= 1.9563 atm
Recall that: 1 atm = 760 mm Hg
Thus:
1.9563 atm = 1.9563 x 760 mm Hg
= 1486.788 mm Hg
In other words, the pressure exerted by the gas in atm is 1.9563 atm and in mm HG is 1486.788 mm Hg.
More on the ideal gas law can be found here: brainly.com/question/28257995
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