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Free_Kalibri [48]
3 years ago
13

Hello how do I solve data for plotting graphs?

Chemistry
1 answer:
OverLord2011 [107]3 years ago
4 0
You could solve it by analyzing the points by graphing them on a coordinate plane
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Use the data set to answer the question.
andrezito [222]

Answer:

It is both accurate and precise.

Explanation:

Precision and accuracy are two different terms used to describe data or measurements. Accuracy refers to how close a set of measurements/experimental values is to an accepted or correct value while Precision refers to how close a series of experimental values are to one another.

In the given set of data in the question below, the Correct Value is 59.2 while the experimental values are as follows;

Trial 1: 58.7

Trial 2: 59.3

Trial 3: 60.0

Trial 4: 58.9

Trial 5: 59.2

Based on comparison, it can be observed that these experimental values are close to the correct value (59.2). Hence, they are said to be ACCURATE. Also, the experimental values are close to one another, hence, they are said to be PRECISE.

Therefore, the data set is both accurate and precise.

7 0
3 years ago
On which of the following factors does the amount of energy absorbed by an endothermic reaction depend?
jolli1 [7]

Answer: D!! ( difference in the potential energy of the reactants and products )

Explanation:

i have the same test

4 0
3 years ago
Which of the following elements has the highest electronegativity?
olga55 [171]
Bromine has the highest
6 0
3 years ago
Laney left a nail in water for two weeks, and the nail became rusted from sitting in the water.
Simora [160]
B) A chemical change because the nail reacts with water/oxygen to create rust (a type of oxide)
5 0
3 years ago
An alloy with an average grain diameter of 35 μm has a yield strength of 163 Mpa, and when it undergoes strain hardening, the gr
Lera25 [3.4K]

Answer:

\sigma_y\ =210.2\ MPa  

Explanation:

Given that

d= 35 μm ,yield strength = 163 MPa

d= 17 μm ,yield strength = 192 MPa

As we know that relationship between diameter and yield strength

\sigma_y=\sigma_o+\dfrac{K}{\sqrt d}

\sigma_y\ =Yield\ strength

d = diameter

K =Constant

\sigma_o\ =material\ constant

So now by putting the values

d= 35 μm ,yield strength = 163 MPa

163=\sigma_o+\dfrac{K}{\sqrt 35}      ------------1

d= 17 μm ,yield strength = 192 MPa

192=\sigma_o+\dfrac{K}{\sqrt 17}           ------------2

From equation 1 and 2

192-163=\dfrac{K}{\sqrt 17}-\dfrac{K}{\sqrt 35}

K=394.53

By putting the values of K in equation 1

163=\sigma_o+\dfrac{394.53}{\sqrt 35}

\sigma_o\ =96.31\ MPa

\sigma_y=96.31+\dfrac{394.53}{\sqrt d}

Now when d= 12 μm

\sigma_y=96.31+\dfrac{394.53}{\sqrt 12}

\sigma_y\ =210.2\ MPa

4 0
3 years ago
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