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Free_Kalibri [48]
3 years ago
13

Hello how do I solve data for plotting graphs?

Chemistry
1 answer:
OverLord2011 [107]3 years ago
4 0
You could solve it by analyzing the points by graphing them on a coordinate plane
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PLEASE HELP ME ITS DUE IN 1 HOUR PLZZZ
Ierofanga [76]
I can’t use evidence from the picture but the green slime from the pond that they are talking about is called Algae, which is alive and can grow quickly with sunlight or any other source of energy such as water and carbon dioxide. Hope this helps!!
5 0
3 years ago
Read 2 more answers
What is the mass, in grams, of
DIA [1.3K]

Answer:

The answers to your question are below

Explanation:

a) 6.85×1020 H2O2 molecules

H2O2   MW = 32 + 2 = 34 g

                                    34g -------------------- 6.023 x 10²³ molecules

                                    x       -------------------  6.85 x 10 ²⁰

                                   x = (6.85 x 10 ²⁰)(34)/  6.023 x 10²³

                                   x = 0.038 g

3.3×1022 SO2 molecules

MW SO2 = 32 + 32 = 64g

                                    64 g -------------------- 6.023 x 10²³ molecules

                                    x      --------------------  3.3×1022 SO2 molecules

                                    x = (3.3×1022 SO2)(64) / 6.023 x 10²³

                                   x = 3.51 g

5.5×1025 O3 molecules

MW = 16 x 3 = 48g

                                 48 g -----------------   6.023 x 10²³ molecules

                                  x     ------------------   5.5×1025 O3 molecules

                               x = (5.5×1025 )(48) /  6.023 x 10²³

                               x = 4383 g

9.30×1019 CH4 molecules

MW = 12 + 4 = 16 g

                              16 g --------------------  6.023 x 10²³ molecules

                              x      --------------------   9.30×1019 CH4 molecules

                           x = (9.30×1019)(16) / 6.023 x 10²³

                           x = 0.0025 g

4 0
3 years ago
Which statement below best describes mutations?
Studentka2010 [4]

Answer:

C. Mutations are a change in DNA or a chromosome and can be helpful, harmful or may have no affect.

Explanation:

  • Mutations are spontaneous random changes that occurs in the genetic make up of an organisms. Mutations are rare and their rate of occurrence is random.
  • Mutations may occur on the gene level known as gene mutations or at chromosome levels called chromosomal mutations.
  • Mutations may be beneficial, harmful or have no effect on a given organisms. Harmful mutations cause disorders that may lead to abnormality or death of an organisms. Beneficial mutations improve an organisms adaptability to the environment.
8 0
3 years ago
For the overall reaction below, which of the following is the correctly written rate law? Overall reaction: O3(g)+2NO2(g)→N2O5(g
zavuch27 [327]

Answer: Rate=k[O_3][NO_2]^2

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

O_3(g)+NO_2(g)\rightarrow NO_3(g)+O_2(g)   slow

NO_3(g)+NO_2(g)\rightarrow N_2O_5(g)   fast

To determine the net chemical equation, we will simply add the above two equations, we get:

O_3(g)+2NO_2(g)\rightarrow N_2O_5(g)+O_2(g)

Rate=k[O_3][NO_2]^2

Order with respect to O_3 is 1 and Order with respect to NO_2 is 2.

Thus the rate law will be:  Rate=k[O_3][NO_2]^2

6 0
3 years ago
A 25.0 mL sample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 37.5
Soloha48 [4]
This is all i know
First of all, let's write the equation of the reaction.
CH₃COOH + NaOH ⇒ CH₃COONa + H₂O
The formula to be used here is CaVa/CbVb = na/nb
where Ca is the concentration of the acid (?)
Cb is the concentration of the base (0.175M)
Va is the volume of the acid (25 mL)
Vb is the volume of the base (37.5 mL)
na is the number of moles of acid (1)
nb is the number of moles of base (1)
Ca × 25/0.175 × 37.5 = 1/1
Ca = 0.175 × 37.5 × 1 /25 ×1
Ca = 0.263 M
The concentration of the acid in the sample was 0.263 M

5 0
3 years ago
Read 2 more answers
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