Answer:
d) V = 91.3 L
Explanation:
Given data:
Volume of nitrogen = ?
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Number of atoms of nitrogen = 2.454×10²⁴ atoms
Solution:
First of all we will calculate the number of moles of nitrogen by using Avogadro number.
1 mole = 6.022×10²³ atoms
2.454×10²⁴ atoms × 1 mol / 6.022×10²³ atoms
0.407×10¹ mol
4.07 mol
Volume of nitrogen:
PV = nRT
1 atm × V = 4.07 mol ×0.0821 atm.L /mol.K ×273.15 K
V = 91.3 atm.L /1 atm
V = 91.3 L
The average weight of an atom of an element, formerly based on the
weight of one hydrogen atom taken as a unit or on 1/16 (0.0625) the
weight of an oxygen atom, but after 1961 based on 1/12 the weight of the
carbon-12 atom.
Given
Mass number of isotope = 63
Number of neutrons = 33
So number of protons = 63 - 33 = 30
Hence atomic number of metal = 30
thus metal is = zinc
now as it is forming cation with 28 electrons it means it has lost two electrons so it must have a dipositive charge
the symbol of metal ion will be
Zn^+2
Organic compounds that contain only hydrogens and carbons are known as hydrocarbons. Hydrocarbons can be saturated or unsaturated in nature. Saturated hydrocarbons are those which contain only carbon-carbon single bonds whereas unsaturated hydrocarbons contain carbon-carbon double or triple bonds. Hydrocarbons can undergo several reactions like substitution, elimination etc.
When one or more hydrogen atoms in hydrocarbon are substituted with halogen it results in the formation of haloalkane. Due to which the molecular weight increases as the halogen atoms are large compared to the carbon and hydrogen atoms. The bond becomes polar due to the presence of electronegative halogen atom and thus results in the increase in boiling point of the haloalkane.
Thus, the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.
