Answer:
a) 0.0130 m
b') w' = =6.46*10^{-3] m
Explanation:
given data:
\lambda of light = 633 nm
width of siit a =0.360 mm
distance from screen = 3.75 m
a) the first minima is located at
=
with of central fringe = 2y_1 = 2*6.54 *10^{-3} = 0.0130 m
b)
width of the first bright fringe on either side of the central one =
calculation for y_2
=
w' = =6.46*10^{-3] m
Answer:
<h3>The answer is 3.81 kg</h3>Explanation:
The mass of the dog can be found by using the formula
f is the force
a is the acceleration
From the question we have
We have the final answer as
<h3>3.81 kg</h3>Hope this helps you
Answer:
The surface tension is 0.0318 N/m and is sufficiently less than the surface tension of the water.
Solution:
As per the question:
Radius of an alveolus, R =
Gauge Pressure inside,
Blood Pressure outside,
Now,
Change in pressure,
Since the alveolus is considered to be a spherical shell
The surface tension can be calculated as:
And we know that the surface tension of water is 72.8 mN/m
Thus the surface tension of the alveolus is much lesser as compared to the surface tension of water.