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IgorC [24]
3 years ago
5

Water has a specific heat of 4.186 J/g°C. How much heat is required to increase 10.0 g of water from 25.0°C to 30.0°C?

Physics
1 answer:
poizon [28]3 years ago
6 0

Answer:

=0.2093J

Explanation:

Heat required(Q) = mcø

= (10/1000)*4.186*(30-25)

= 0.2093J

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Answer:

1.35 A

Explanation:

Applying,

V = IR

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But,

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V = AV/Lρ............... Equation 3

From the question,

Given: V = 0.7 V, A = 0.290 mm² = 2.9×10⁻⁷ m², L = 1.5 m, ρ = 10×10⁻⁸ Ω.m

Substitute these values into equation 3

I = (0.7× 2.9×10⁻⁷)/(1.5× 10×10⁻⁸ )

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