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Leokris [45]
3 years ago
15

The Voltage difference of a circuit is 16V and the resistance is 120 ohms. What is the current in the circuit? Show me your work

please!
Physics
1 answer:
Ganezh [65]3 years ago
7 0

Answer:

0.133 A

Explanation:

Given:

The voltage difference is, V=16\ V

The resistance of the circuit is, R=120\ ohms

Now, as per Ohm's Law, the potential difference across two points in a circuit is directly proportional to the current supplied in the circuit. The constant of proportionality is the resistance of the circuit.

Hence, the mathematical statement of Ohm's law is given as:

V=IR Where I is the current in the circuit.

Now, plug in 16 for 'V' and 120 for 'R' and solve for 'I'. This gives,

16=120I\\I=\frac{16}{120}\\I=0.133\ A

Therefore, the current in the circuit is 0.133 amperes.

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Aleks04 [339]

Answer: The keywords to input into the blank spaces were omitted which are ; fragments, increases, decreases, opaque, raises, molecular, protostar, gravitational, thermal.

Please find the answers for the blank spaces in the explanation column

Explanation:

1. The first stage of stellar formation is the assembly (or formation) of a_PROTOSTAR______ . 2. Stars form in MOLECULAR clouds. 3. When a cloud collapses, it FRAGMENTS into smaller and smaller pieces till those pieces reach stellar masses. 4. As the density increases, the fragments become_OPAQUE______ , which___RAISES_____ the temperature of the cloud and inhibits further fragmentation. 5. The __FRAGMENTS_____then condense into rotating globs of gas that serve as stellar embryos. 6. During this stage the surface temperature INCREASES_______ and luminosity__INCREASES_______ despite decreasing size. 7. The central temperature and pressure increase as the GRAVITATIONAL potential energy is converted to energy due to THERMAL contraction.

The above describes the evolution or formation of stars which begins with the collapse of a molecular cloud by gravitational force, this collapse cause the molecular cloud to fragment with the release of heat --Gravitation potential energy causing an increased temperature and pressure of the newly condensing  fragment with increasing luminosity known as a Protostar.

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3 years ago
Calculate the volume of a 45 kg bucket knowing its density which is 2.7 kg/m3 (cubic meters)
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In a collision an object experiences impulses , this impulse can be determined by
astraxan [27]

In a collision an object experiences impulses, this impulse can be determined by the product of net force exerted upon it in the specific course of time.

<u>Explanation:</u>

An object experiences impulse due to the force exerted upon it in a particular time period.

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Where,

F - Force acted upon the object

\Delta t - time interval for which the force act

According to the definition of Impulse, it is the integral of force (F) that acts upon any object over a time interval ∆t. It produces an equivalent change in the momentum and that too in the same direction as of the applied force (F).

Therefore, in order to find the impulse on an object, we have to find the force acted on it in a specific time interval.

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A sprinter is advised to reduced his speed slowly after completing his race.why
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<span>The sprinter is advised to reduce his speed slowly after completing the race because of the power that is needed when the stoppage is down in a faster manner could be very great. This would translate to the great usage in gasoline. Also, the inertia of the vehicle is quiet high so it is hard to stop it very suddenly. </span>

5 0
3 years ago
Two Carnot air conditioners, A and B, are removing heat from different rooms. The outside temperature is the same for both rooms
amid [387]

Answer:

a) Work required for air conditioner A = 354.7 J

b) Work required for air conditioner B = 310.3 J

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d) The magnitude of the heat deposited outside for conditioner B = 4640.3 J

Explanation:

In a carnot air conditioner, it operates like a reverse carnot engine; i.e. it removes heat from the cold reservoir (making it colder) and dumps the heat in the hot reservoir (making it hotter)

For a Carnot air conditioner,

Q꜀ is the heat removed from the colder reservoir = 4330 J for both cases

T꜀ is the temperature of the colder reservoir (temperature of the rooms) = 293 K and 296 K for both cases to be considered.

Qₕ is the heat deposited in the warmer reservoir = ? for both cases

Tₕ is the temperature of the hot reservoir (temperature of outside) = 317 K for both cases.

For Carnot air conditioners,

Qₕ = W + Q꜀ (eqn 1)

And

(Qₕ/Tₕ) - (Q꜀/T꜀) = 0 (eqn 2)

Making Qₕ the subject of formula in eqn 2

Qₕ = Tₕ (Q꜀/T꜀)

Substituting this into eqn 1

Tₕ (Q꜀/T꜀) = W + Q꜀

Q꜀ (Tₕ/T꜀) - Q꜀ = W

Q꜀ [(Tₕ - T꜀)/T꜀ ] = W

W = Q꜀ [ (Tₕ - T꜀)/T꜀ ]

For the air conditioner A,

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W = Q꜀ [ (Tₕ - T꜀)/T꜀ ] = 4330 [ (317 - 293)/293] = 354.7 J

For the air conditioner B,

T꜀ = 296 K, Tₕ = 317 K, Q꜀ = 4330 J, W = ?

W = Q꜀ [ (Tₕ - T꜀)/T꜀ ] = 4330 [ (317 - 296)/296] = 310.3 J

c) Qₕ = W + Q꜀

For conditioner A,

Qₕ = 354.7 + 4330 = 4684.7 J

For conditioner B,

Qₕ = 310.3 + 4330 = 4640.3 J

8 0
3 years ago
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