Answer:
![r=2.3808\ \Omega](https://tex.z-dn.net/?f=r%3D2.3808%5C%20%5COmega)
Explanation:
Given:
- power of battery,
![P_b=16.2\ W](https://tex.z-dn.net/?f=P_b%3D16.2%5C%20W)
- voltage across the load resistor,
![V=13.3\ V](https://tex.z-dn.net/?f=V%3D13.3%5C%20V)
- emf of the battery,
![emf=16.2\ V](https://tex.z-dn.net/?f=emf%3D16.2%5C%20V)
<u>Now as we know that the electric power is given as:</u>
![P_b=\frac{V^2}{R}](https://tex.z-dn.net/?f=P_b%3D%5Cfrac%7BV%5E2%7D%7BR%7D)
here:
resistance of the load
a)
Now the load resistance:
![R=\frac{V^2}{P_b}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7BV%5E2%7D%7BP_b%7D)
![R=\frac{13.3^2}{16.2}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B13.3%5E2%7D%7B16.2%7D)
![R=10.92\ \Omega](https://tex.z-dn.net/?f=R%3D10.92%5C%20%5COmega)
b)
Using Ohm's law, current in the load:
![I=\frac{V}{R}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7BV%7D%7BR%7D)
![I=\frac{13.3}{10.92}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B13.3%7D%7B10.92%7D)
![I=1.218\ A](https://tex.z-dn.net/?f=I%3D1.218%5C%20A)
Now,
![emf-V=r.I](https://tex.z-dn.net/?f=emf-V%3Dr.I)
where:
internal resistance
![16.2-13.3=r\times 1.218](https://tex.z-dn.net/?f=16.2-13.3%3Dr%5Ctimes%201.218)
![r=2.3808\ \Omega](https://tex.z-dn.net/?f=r%3D2.3808%5C%20%5COmega)
Answer:
706.5 g
Explanation:
density of fluid, d = 1.35 g/c.c
According to the principle of flotation
Weight of the frog = Buoyant force acting on the frog
V x density of frog x g = V x density of fluid x g
So, the density of frog = density of pod
Mass of frog = volume of frog x density of frog
M = 4/3 πr³ x d
M = 4/3 x 3.14 x 5 x 5 x 5 x 1.35
M = 706.5 g
Thu,s the mass of frog is 706.5 g .
The distance at which the sound level is 100 dB is 30m.
<h3>
What is distance?</h3>
Distance is a measurement of how far apart two objects or locations are. Distance in physics or common language can refer to a physical length or an estimate based on other factors (e.g. "two counties over"). |AB| is a symbol that can be used to represent the distance between two points. "Distance from A to B" and "Distance from B to A" are frequently used interchangeably. A distance function or metric is a technique to describe what it means for elements of some space to be "close to" or "far away" from each other in mathematics. It is a generalization of the idea of physical distance. Distance is a non-numerical unit of measurement in psychology and other social sciences.
Explanation:
We anticipate the radial distance to be 10 times greater, or 30 m, when the intensity is reduced by 20 dB, or by a factor of 102. A further 90 dB reduction might translate to an additional factor of 104.5 in terms of distance, or roughly 3030000m or 1000 miles. We measure sound intensity using the inverse square law and the decibel scale definition. According to the sound level definition,
β=10log![(\frac{1}{10^{-12}W/m^{2} } )](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B10%5E%7B-12%7DW%2Fm%5E%7B2%7D%20%20%7D%20%29)
We can compute the intensities corresponding to each of the levels mentioned as
![I=[10^{\frac{\beta }{10} } ]10^{-12} W/m^{2}](https://tex.z-dn.net/?f=I%3D%5B10%5E%7B%5Cfrac%7B%5Cbeta%20%7D%7B10%7D%20%7D%20%5D10%5E%7B-12%7D%20W%2Fm%5E%7B2%7D)
a. The power passing through any sphere around the source is
P=4π
l
If we ignore absoption of sound by the medium,
conservation of energy requires that
![r_{120} ^{2} I_{120} = r_{100}^{2} I_{100} =r_{10} ^{2} I_{10}](https://tex.z-dn.net/?f=r_%7B120%7D%20%5E%7B2%7D%20I_%7B120%7D%20%3D%20r_%7B100%7D%5E%7B2%7D%20%20I_%7B100%7D%20%3Dr_%7B10%7D%20%5E%7B2%7D%20I_%7B10%7D)
then,![r_{100} =r_{120} \sqrt{x} \frac{I_{120} }{I_{100} } =(3.00m)\sqrt{\frac{1\frac{W}{m^{2} } }{10^{-2}\frac{W}{m^{2} } } } =30 m](https://tex.z-dn.net/?f=r_%7B100%7D%20%3Dr_%7B120%7D%20%5Csqrt%7Bx%7D%20%5Cfrac%7BI_%7B120%7D%20%7D%7BI_%7B100%7D%20%7D%20%3D%283.00m%29%5Csqrt%7B%5Cfrac%7B1%5Cfrac%7BW%7D%7Bm%5E%7B2%7D%20%7D%20%7D%7B10%5E%7B-2%7D%5Cfrac%7BW%7D%7Bm%5E%7B2%7D%20%7D%20%20%7D%20%7D%20%3D30%20m)
To learn more about distance ,visit:
brainly.com/question/21967820
#SPJ4
Since speed (v) is in ft/sec, let's convert our diameters from inches to feet:
1) 5/8in = 0.625in
0.625in × 1ft/12in = 0.0521ft
2) 0.25in × 1ft/12in = 0.021ft
Equation:
![v = 4q \div ( {d}^{2} \pi) \: where \: q = flow \\ v = velocity \: (speed) \: and \: \\ d = diameter \: of \: pipe \: or \: hose \\ and \: \pi = 3.142](https://tex.z-dn.net/?f=v%20%3D%204q%20%5Cdiv%20%28%20%7Bd%7D%5E%7B2%7D%20%5Cpi%29%20%5C%3A%20where%20%5C%3A%20q%20%3D%20flow%20%5C%5C%20v%20%3D%20velocity%20%5C%3A%20%28speed%29%20%5C%3A%20and%20%5C%3A%20%20%5C%5C%20d%20%3D%20diameter%20%5C%3A%20of%20%5C%3A%20pipe%20%5C%3A%20or%20%5C%3A%20hose%20%5C%5C%20and%20%5C%3A%20%5Cpi%20%3D%203.142)
![we \: can \: only \: assume \:that \\ flow \: (q) \:stays \: same \: since \: it \\ isnt \: impeded \: by \: anything \\ thus \:it \: (q)\: stays \: the \: same \: \\ so \: 4q \: can \: be \: removed \: from \: \\ the \: equation](https://tex.z-dn.net/?f=we%20%5C%3A%20can%20%5C%3A%20only%20%5C%3A%20assume%20%5C%3Athat%20%5C%5C%20%20flow%20%5C%3A%20%28q%29%20%5C%3Astays%20%5C%3A%20same%20%5C%3A%20since%20%5C%3A%20it%20%5C%5C%20%20isnt%20%5C%3A%20impeded%20%5C%3A%20by%20%5C%3A%20%20anything%20%5C%5C%20thus%20%5C%3Ait%20%20%5C%3A%20%28q%29%5C%3A%20%20stays%20%5C%3A%20the%20%5C%3A%20same%20%5C%3A%20%20%5C%5C%20so%20%5C%3A%204q%20%5C%3A%20can%20%5C%3A%20be%20%5C%3A%20removed%20%5C%3A%20from%20%5C%3A%20%20%5C%5C%20the%20%5C%3A%20equation)
![then \: we \: can \: assume \: that \: only \\ v \: and \: d \: change \: leading \:us \: to > > \\ (v1 \times {d1}^{2} \pi) = (v2 \times {d2}^{2}\pi)](https://tex.z-dn.net/?f=then%20%5C%3A%20we%20%5C%3A%20can%20%5C%3A%20assume%20%5C%3A%20that%20%5C%3A%20only%20%5C%5C%20v%20%5C%3A%20and%20%5C%3A%20d%20%5C%3A%20change%20%5C%3A%20leading%20%5C%3Aus%20%5C%3A%20to%20%3E%20%20%3E%20%20%5C%5C%20%28v1%20%5Ctimes%20%7Bd1%7D%5E%7B2%7D%20%5Cpi%29%20%3D%20%28v2%20%20%5Ctimes%20%20%20%7Bd2%7D%5E%7B2%7D%5Cpi%29%20)
![both \: \pi \: will \: cancel \: each \: other \: out \: \\ as \: constants \:since \: one \: is \: on \\ each \: side \: of \: the \: =](https://tex.z-dn.net/?f=both%20%5C%3A%20%5Cpi%20%5C%3A%20will%20%5C%3A%20cancel%20%5C%3A%20each%20%5C%3A%20other%20%5C%3A%20out%20%5C%3A%20%20%5C%5C%20as%20%5C%3A%20constants%20%5C%3Asince%20%5C%3A%20one%20%5C%3A%20is%20%5C%3A%20on%20%5C%5C%20each%20%5C%3A%20side%20%5C%3A%20of%20%5C%3A%20the%20%5C%3A%20%20%3D%20%20%20)
![(v1 \times {d1}^{2}) = (v2 \ \times {d2}^{2}) \\ (7.0 \times {0.052}^{2}) = (v2 \times {0.021}^{2}) \\ divide \: both \: sides \: by \: {0.021}^{2} \\ to \: solve \: for \: v2 > >](https://tex.z-dn.net/?f=%28v1%20%20%5Ctimes%20%20%20%7Bd1%7D%5E%7B2%7D%29%20%3D%20%28v2%20%5C%20%5Ctimes%20%7Bd2%7D%5E%7B2%7D%29%20%5C%5C%20%287.0%20%5Ctimes%20%20%20%7B0.052%7D%5E%7B2%7D%29%20%3D%20%28v2%20%20%5Ctimes%20%20%20%7B0.021%7D%5E%7B2%7D%29%20%5C%5C%20divide%20%5C%3A%20both%20%5C%3A%20sides%20%5C%3A%20by%20%5C%3A%20%20%7B0.021%7D%5E%7B2%7D%20%5C%5C%20to%20%5C%3A%20solve%20%5C%3A%20for%20%5C%3A%20v2%20%3E%20%20%3E%20%20)
![v2 = (7.0)( {0.052}^{2} ) \div ( {0.021}^{2}) \\ v2 = (7.0)(.0027) \div (.00043) \\ v2 = 44 \: feet \: per \: second](https://tex.z-dn.net/?f=v2%20%3D%20%287.0%29%28%20%7B0.052%7D%5E%7B2%7D%20%29%20%5Cdiv%20%28%20%7B0.021%7D%5E%7B2%7D%29%20%20%5C%5C%20v2%20%3D%20%287.0%29%28.0027%29%20%5Cdiv%20%28.00043%29%20%5C%5C%20v2%20%3D%2044%20%5C%3A%20feet%20%5C%3A%20per%20%5C%3A%20second)
new velocity coming out of the hose then is
44 ft/sec
Answer:
Due to the Electric Charge Conservation Law, the statement is <u><em>true.</em></u>
Explanation:
Conservation laws state that the physical properties or magnitudes of a given system have a constant value, that is, they cannot change.
Electric charge is a property that exists in some subatomic particles, manifested by attractions and repulsions that give rise to electromagnetic interactions.
The electric charge is governed by the principle of conservation of the charge. This law establishes that the total load in an isolated system is constant, that is, it is not possible to create or destroy isolated loads. That is, they can only be moved from one body to another or from one place to another inside the given body.
As mentioned, this law is only valid for closed systems in which no charged particles enter or leave outside. Then it is concluded that the algebraic sum of the charges of all particles remains constant.
Finally, <u><em>due to the Electric Charge Conservation Law, the statement is true.</em></u>