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CaHeK987 [17]
3 years ago
6

Explain the difference between speed and velocity and indicate if these are scalar or vector quantities

Physics
1 answer:
Natali5045456 [20]3 years ago
3 0
Speed can never be negative because it does not depend in which direction the car moves whereas, velocity will change if a car turns from due North to East.
Quantities which can be described only by their magnitudes are called scalars and those which are described by both, magnitude and direction are vectors
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Picking up a hot coal is an example of what type of heat transfer?
Zanzabum

That would be a conduction.

7 0
3 years ago
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Mars completes one orbit around the Sun in approximately two Earth years. Mars orbits at an average distance to the Sun of about
satela [25.4K]

Answer:

about 0.8 times

Explanation: MARS is a planet named after a Roman God of War, it is the fourth planet from the sun and the Second smallest planet following Mercury.

The orbital Speed of a planet is the speed with which the planet uses to completely go round the Sun.

The orbital Speed of the Earth is 29.78kilmeters per Second.

The orbital Speed of Mar is 0.8*29.78kilometers per second/1

=23.824kilmeters per second.

3 0
3 years ago
What is the speed of an object that travels 20 meters in 4 seconds?
Iteru [2.4K]

Given:-

  • Distance covered by the particle (s) = 20 m
  • Time taken (t) = 4 seconds

To Find: Speed of it.

We know,

v = s/t

where,

  • v = Speed,
  • s = Distance &
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Putting the values,

v = (20 m)/(4 s)

→ v = 5 m/s (Ans.)

5 0
3 years ago
Two point charges, 3.4 μC and -2.0 μC , are placed 5.0 cm apart on the x axis. Assume that the negative charge is at the origin,
Elza [17]

The electric field is zero at x = -16.45cm

Data;

  • q1 = 3.4 μC
  • q2 = -2.0 μC
  • distance = 5cm

<h3>The Electric Field at point 0</h3>

As the 3μC is larger than -2.0μC  and the charges are opposite sign. The electric field will be zero at the negative axis.

Let the point be at x.

For an electric field to be equal to zero;

k(\frac{q_1}{d_1})^2 + k(\frac{q_2}{d_2})^2 = 0\\\frac{3.4}{(5-x)^2} - \frac{2}{x^2} = 0\\

Let's solve for x using mathematical methods.

\frac{3.4x^2 - 2(5-x)^2}{(5-x)^2x^2}= 0\\ 3.4x^2 - 2(5-x^2) = 0\\3.4x^2 - 50 - 2x^2 + 20x = 0\\1.4x^2 +20x - 50 = 0

Solving the above quadratic equation;

x = -16.45cm

The electric field is zero at x = -16.45cm

Learn more on electric field at a point here;

brainly.com/question/1592046

brainly.com/question/14372859

8 0
2 years ago
Which one of the following statements about attitudes is correct?
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B is a correct answer. Positive attitudes can help us learn quicker. Hope it helped you, and have a great day.

-Charlie
7 0
3 years ago
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