Kinetic energy =1/2 mv^2 
<span>m=2ke/v^2 </span>
<span>m=2(34)/3.6^2 </span>
<span>m=5.24 </span>
<span>force normal = mg </span>
<span>=5.24 x 9.8 </span>
<span>force normal = 51.4N
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The Image distance and Magnification of The Image will be 30 cm and 3.
<h3>What is focal length?</h3>
The focal length of the lens, which is often expressed in millimeters, is the distance between the lens and the image sensor when the subject is in focus.
Given data;
Focal length,f=?
Image distance,v=?
Object distance,u= 10 cm
Magnification,m= 2.85
The focal length is half of the radius;
f=R/2
f=30 Cm/2
f= 15 Cm
The mirror equation is found as;

The magnification of the lens is found as;

Hence, the image distance and magnification of The image will be 30 cm and 3.
To learn more about the focal length refer;
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C. It is answered by observation and evidence.
Good scientific explanations are defined, measurable and controllable. They can be answered by an experiment.
 
        
             
        
        
        
Decreasing the distance between two objects having a considerable mass would increase the attraction on gravitation. The reverse is true that if you separate or inrease the objects distance would substantially decrease their gravitational attraction. Most object in our planet is held by its gravitational force towards it's center.