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Komok [63]
2 years ago
14

Volleyball took some of its characteristics from handball and tennis True False

Physics
1 answer:
lana [24]2 years ago
6 0

Answer:

True Because if we observe carefully we will see that some moves of volleyball are similar to handball and tennis

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A circuit contains a single 220 pF capacitor hooked across a battery. It is desired to store three times as much energy in a com
Anettt [7]

Answer

The capacitor should be connected in parallel as parallel connection gives the arithmetic sum of capacitance which will give a corresponding sum of energy while capacitors in series gives the sum of the reciprocal if the individual capacitance

7 0
3 years ago
If an object force of 50 N is used to move an object a distance of 20 m, what distance must the object be moved if the input for
steposvetlana [31]

Answer:

\ d_{out} = 100 \ m.

Explanation:

Given data:

F_{in} = 50 \ \rm N

F_{out} = 10 \ \rm N

d_{in} = 20 \ m

Let the distance traveled by the object in the second case be d_{out}.

In the given problem, work done by the forces are same in both the cases.

Thus,

W_{in} = W_{out}

F_{in}.d_{in} = F_{out}.d_{out}

\Rightarrow \ d_{out} = \frac{F_{in}.d_{in}}{F_{out}}

\ d_{out} = \frac{50 \times 20}{10}

\ d_{out} = 100 \ m.

5 0
3 years ago
Which of the following types of particles can be categorized into different kind of elements?
KatRina [158]

The answer would be atoms

4 0
2 years ago
Read 2 more answers
Knowing Newton’s 2nd Law, how would you rearrange it to solve for acceleration.
AysviL [449]

Answer:

Force / mass

Explanation:

Divide mass on both sides to get acceleration by itself leaving you with mass below force hence divide force by mass

8 0
3 years ago
Read 2 more answers
You throw a stone horizontally at a speed of 5.0 m/s from the top of a cliff that is 78.4 m high.
Monica [59]

a)You throw a stone horizontally at a speed of 5.0 m/s from the top of a cliff that is 78.4 m high.

from above statement we got

height = 78.4 m

since the ball is thrown, so its vertical velocity would be zero

u = 0

taking g = 9.8m/s^2

now, using the equation of motion

h = ut + gt^2/2

now putting all the values in it

we got ,

78.4 = 9.8 * t^2/ 2

by solving we got,

t = 4 sec

b) now, since along the horizontal , no force acting and accelaration is zero so

R = ut , R is RANGE

R = 5 * 4

range =  20 m

c)  vertical components of the stone’s velocity just before it hits the ground = v sin θ =

horizontal   components of the stone’s velocity  just before it hits the ground = v cos θ

To know more about velocity  visit :

brainly.com/question/18084516

#SPJ9

4 0
1 year ago
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