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satela [25.4K]
3 years ago
13

If 89.6 joules of heat 20.0 grams of iron from 30.0 C to 40.0 C, what is the specific heat of the iron in J/g.C?

Chemistry
1 answer:
atroni [7]3 years ago
4 0

Answer:

 

H = m c ΔT  

89.6 J = (20.0 g) × c × (40.0 - 30.0)°C  

Specific heat of iron, c = 89.6 / [20.0 × (40.0 - 30.0)] J/(g°C) = 0.448 J/(g°C)

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To know more about reaction

brainly.com/question/20305735

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