3 years ago

If 89.6 joules of heat 20.0 grams of iron from 30.0 C to 40.0 C, what is the specific heat of the iron in J/g.C?

Chemistry

1 answer:

atroni [7]3 years ago

4 0

Answer:

H = m c ΔT

89.6 J = (20.0 g) × c × (40.0 - 30.0)°C

Specific heat of iron, c = 89.6 / [20.0 × (40.0 - 30.0)] J/(g°C) = 0.448 J/(g°C)

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An aqueous solution containing 10 g of an optically pure compound was diluted to 500 mL with water and was found to have a speci

lapo4ka [179]

Answer:

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Also,

Optical purity = $\frac {optical\ rotation\ of\ mixture}{optical\ rotation\ of\ pure\ enantiomer}\times 100$

Optical rotation of pure enantiomer = −127 °

$76.9231=\frac {optical\ rotation\ of\ mixture}{-127^0}\times 100$

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