Answer is: new substance.
For example, synthesis chemical reaction: Ba + F₂ → BaF₂.
Synthesis reaction is a type of reaction in which multiple reactants combine to form a single product.
New substance, barium fluoride is formed, with different chemical and ohysical properties than reactants (barium and fluorine).
In barium fluoride, barium has oxidation number +2 and fluorine has oxidation number -1, so compound has neutral charge.
they would be more detailed? what type of cells though?
Equation of reaction
Hcl+NaoH-->Nacl+H2O
1:1
Using the formula CaVa/CbVb=na/nb
Ca(Concentation of acid)= 0.100M
Cb(Concentration of base)=0.200M
Va=?
VB=50.00ml
na=1
nb=1
from the formula
Va= CbVbna/Canb
Va= 0.2*50*1/0.1*1
=10/0.1=100ml
Therefore volume of acid = 100ml
Answer:
9.63 L of NO
Explanation:
We'll begin by calculating the number of mole in 50.0 g of NH₄ClO₄. This can be obtained as follow:
Mass of NH₄ClO₄ = 50 g
Molar mass of NH₄ClO₄ = 14 + (4×1) + 35.5 + (16×4)
= 14 + 4 + 35.5 + 64
= 117.5 g/mol
Mole of NH₄ClO₄ =?
Mole = mass /molar mass
Mole of NH₄ClO₄ = 50/117.5
Mole of NH₄ClO₄ = 0.43 mole
Next, we shall determine the number of mole of NO produced by the reaction of 50 g (i.e 0.43 mole) of NH₄ClO₄. This can be obtained as follow:
3Al + 3NH₄ClO₄ –> Al₂O₃ + AlCl₃ + 3NO + 6H₂O
From the balanced equation above,
3 moles of NH₄ClO₄ reacted to produce 3 moles of NO.
Therefore, 0.43 mole of NH₄ClO₄ will also react to produce 0.43 mole of NO.
Finally, we shall determine the volume occupied by 0.43 mole of NO. This can be obtained as follow:
1 mole of NO = 22.4 L
Therefore,
0.43 mole of NO = 0.43 × 22.4
0.43 mole of NO = 9.63 L
Thus, 9.63 L of NO were obtained from the reaction.
We can solve this problem by using Henry's law.
Henry's law states that the amount of dissolved gas is proportional to its partial pressure.
![C=kP](https://tex.z-dn.net/?f=C%3DkP)
C is <span>the solubility of a gas.
</span><span>k is Henry's law constant.
</span><span>P is the partial pressure of the gas.
</span>We can calculate the constant from the first piece of information and then use Henry's law to calculate solubility in open drink.
0.12=4k
k=0.03
Now we can calculate the solubility in open drink.
![C_o=kP_o ](https://tex.z-dn.net/?f=C_o%3DkP_o%0A)
![C_o=0.03 \cdot 3\cdot 10^{-4}=0.09\cdot 10^{-4} \frac{mol}{L}](https://tex.z-dn.net/?f=C_o%3D0.03%20%5Ccdot%20%203%5Ccdot%2010%5E%7B-4%7D%3D0.09%5Ccdot%2010%5E%7B-4%7D%20%5Cfrac%7Bmol%7D%7BL%7D%20)
Now we need to convert it to g/L. One mol of CO2 is 44.01<span>g.
</span>The final answer is: