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2 years ago

PLZ HELP NOW!!!!!!

2 answers:

7 0

A right triangle ABC is formed when we join three points around a lake. Length of the side AC = 6 miles. Length of the side BC = 2 miles. We have to find Length of side AB.Using Pythagorean theorem for Right triangle ABC , Right angled at B→AB² + BC²= AC²→ AB² + 2²= 6²→ AB² = 36 - 4→ AB²= 32→ AB = √ 32→→AB = 5.66 (approx)Option (B) AB = 5.66 is Right choice.

amid [387]2 years ago

3 0

Answer:

AB+ BC^2= AC

AB^2+ 2^2= 6^2

AB^2 = 36 - 4

AB^2= 32

AB = sqrt 32

AB = 5.66 (approx)

Option (B) AB = 5.66 is Right choice.

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Solve the problem<br> -4p - 4p

Minchanka [31]

$\bold{Hey\ there!}$

$\bold{-4p - 4p = \ ?}\\\ \bold{-4 - 4 = -8}\\\bold{-p - p = -p}\\\bold{-4p - 4p=\underline{-8p}}\\\boxed{\boxed{\bold{Answer: -8p}}}\checkmark$

$\text{\bold{Good luck on your assignment and enjoy your day!}}$

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6 0

2 years ago

Read 2 more answers

25 POINTS

uysha [10]

Answer:

a reflection over the x-axis and then a 90 degree clockwise rotation about the origin

Step-by-step explanation:

Lets suppose triangle JKL has the vertices on the points as follows:

J: (-1,0)

K: (0,0)

L: (0,1)

This gives us a triangle in the second quadrant with the 90 degrees corner on the origin. It says that this is then transformed by performing a 90 degree clockwise rotation about the origin and then a reflection over the y-axis. If we rotate it 90 degrees clockwise we end up with:

J: (0,1) , K: (0,0), L: (1,0)

Then we reflect it across the y-axis and get:

J: (0,1), K:(0,0), L: (-1,0)

Now we go through each answer and look for the one that ends up in the second quadrant;

If we do a reflection over the y-axis and then a 90 degree clockwise rotation about the origin we end up in the fourth quadrant.

If we do a reflection over the x-axis and then a 90 degree counterclockwise rotation about the origin we also end up in the fourth quadrant.

If we do a reflection over the x-axis and then a reflection over the y-axis we also end up in the fourth quadrant.

The third answer is the only one that yields a transformation which leads back to the original position.

4 0

2 years ago

Read 2 more answers

Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74

lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0

3 years ago

Question 5

Darina [25.2K]

Answer:

the answer is 12.24 .

Step-by-step explanation:

that answer is right is because when you add of those you get 530 , then you divide by how many numbers there are which is 7 , which equals to 75.7 . when you get that number ( 75.7) you subtract that number to 65,90,85,70,70,95, and 55 . when you get the total of all of those you add those . which is 10.7, 14.3 , 9.3 , 5.7 , 5.7 , 19.3 , and 20.7 . from adding those you get 85.7. you divide by 7 and get 12.24 . hope this helps :) .

8 0

2 years ago

Please answer this question ‍♀️

krek1111 [17]

Answer:

sum is 1,2,4,8,16,32,64,128,256,512

5 0

2 years ago