Answer:
g=3 yards
Step-by-step explanation:
Since the 3yd on the big triangle is reduced to 1 yd on the small triangle divide 9 by 3 to get the missing side length of 3 yards. Hope this helps :)
<u>Answer:
</u>
The value of the exponential expression
is 2
<u>Solution:</u>
16 superscript one-fourth= 
As per the problem,
We have to find the value of
16 in terms of 2 can be written as 
= 
=
As per the exponential rule, 
=
Here, 
= 
= 2
Hence, the value is 2.
That would be 100 * sin 30 = 100 * 0.5 = 50 pounds
The answer is 79 im sure of it
Answer:
B. 2x – 1 = 13 and x = 7
Step-by-step explanation:
We are given 4 equations and a solution for each. We have to tell which of the given solution satisfies the given equation.
Option A.
2x -1 = 13 and x = 6
Using this value in the equation, we get:
2(6) -1 = 13
12 - 1 = 13
11 = 13, which is not true. Hence this option is not valid
Option B.
2x - 1 = 13 and x = 7
Using the value in the equation, we get:
2(7) - 1 =13
14 - 1 =13
13 = 13, which is true. Hence this option is valid.
Option C.
2x + 1 =13 and x = 7
Using the value in the equation, we get:
2(7) + 1 = 13
15 = 13, which is not true. So this option is not valid
Option D.
2x - 1 = 13 and x = 11
Using this value in the equation, we get:
2(11) - 1 = 13
21 = 13, which is not true. Hence this option is not valid.