Question

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Need help with this one ~

Thanks for Answering !​

Answer 1

Answer:

Hey There!

Let's solve...

I think your diagram must be similar to whatever i drew on attachment...

Now.....

$n_{1} = ma_{1} \\ \\ mg - f_{1} - t = 2ma_{1} \\ \\ mg - \mu _{1} ma_{1} - t = 2ma_{1} \\ \\ t = mg - ma_{1}( \mu_{1} + 2 )$

Lets solve bigger block which is along vertical

$n_{2} = mg + f_{1} + t \\ \\ n_{2} = mg + \mu_{1} ma_{1} + mg - \\ ma_{1} ( \mu_{1} + 2 ) \\ \\ n_{2} = (m + m)g - 2ma_{1}$

Lets solve it horizontally

$2t - n_{1} - f_{2} = ma_{1} \\ \\ 2mg - 2ma_{1}( \mu_{1} + 2) - ma_{1} \\ - \mu_{2} n_{2} = ma_{1}$

$2mg - \mu_{2} n_{2} = a_{1}(m + m + 2m\mu_{1} + 4_{m})$

$2mg - \mu_{2}^{(m + m)}g + \mu_{2}2ma_{1} \\ \\ = a_{1}(m + 5m + 2 \mu_{1}) \\ \\ g(2m - \mu_{2}m - \mu_{2}m) = \\ \\ a_{1}(m + 5m + 2 \mu_{1} - 2 \mu_{2})$

Final answer is just make fraction of that

$a_{1} = \frac{g(2m - \mu _{2}m - \mu_{2}m )}{(m + 5m + 2m \mu_{1} - 2m \mu_{2})}$

so it is your answer.....

I hope it is helpful to you....

Cheers!___________