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Sidana [21]
3 years ago
11

Leandra was dissolving ammonia gas in water. In this example, the ammonia gas is

Chemistry
1 answer:
Ymorist [56]3 years ago
5 0

The Ammonia gas is the solute

  • <u>Solute</u><u>:</u><u>-</u><u> </u><em>The</em><em> </em><em>substance</em><em> </em><em>that</em><em> </em><em>is</em><em> </em><em>being</em><em> </em><em>dissolved</em><em> </em><em>is</em><em> </em><em>called</em><em> </em><em>Solute</em><em>.</em>
  • <u>Solvent</u><u>:</u><u>-</u><u> </u><em>The</em><em> </em><em>substance</em><em> </em><em>in</em><em> </em><em>which</em><em> </em><em>things</em><em> </em><em>are</em><em> </em><em>being</em><em> </em><em>dissolved</em><em> </em><em>is</em><em> </em><em>called</em><em> </em><em>solvent</em><em>.</em>
  • <u>Solution</u><u>:</u><u>-</u><u> </u><em>The</em><em> </em><em>final</em><em> </em><em>product</em><em> </em><em>formed</em><em> </em><em>after</em><em> </em><em>mixing</em><em> </em><em>Solute</em><em> </em><em>with</em><em> </em><em>solvent</em><em> </em><em>is</em><em> </em><em>called</em><em> </em><em>solution</em><em>.</em><em> </em>
  • <u>*</u><u>Note</u><u>:</u><u>-</u><u> </u><u>The</u><u> </u><u>substance</u><u> </u><u>which</u><u> </u><u>has</u><u> </u><u>more</u><u> </u><u>concentration</u><u> </u><u>is</u><u> </u><u>considered</u><u> </u><u>as</u><u> </u><u>solvent</u><u>.</u>
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Several balloons are inflated with helium to a volume of 0.75 L at 27°C. One of the balloons was found several
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Answer:

V₂ = 0.74 L

Explanation:

Given data:

Initial volume of balloon = 0.75 L

Initial temperature of balloon = 27°C (27+273.15 K = 300.15 K)

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Solution:

V₁/T₁ = V₂/T₂

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According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

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3 years ago
Calculate the volume occupied by 0.845 mole of nitrogen gas, the pressure, and the temperature. Find the volume.
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Answer:

V = 15.9512 dm³

Explanation:

Given data:

Pressure = P = 1.37 atm

Temperature = T= 315 K

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Volume = V = ?

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V = nRT/ P

V = ( 0.845 mol× 0.0821 dm³.atm.K⁻¹.mol⁻¹ × 315 K) / 1.37 atm

V = 21.853 dm³. atm/  1.37 atm

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